我一直在终端上收到一个bug，它说：

warning: format specifies type 'char *' but the argument has type 'int' [-Wformat]
    scanf("%c", namehumaninput);
           ~~   ^~~~~~~~~~~~~~

我正在学习的课程是说我所需要做的就是有一个char变量，这就是它，使用它没有别的，但显然有什么是错误的。以下是我遇到麻烦的代码：

//Lesson 9
    int inputage;
    double gpainput;
    char namehumaninput;
    printf("Wat ur age?\n");
    scanf("%d", &inputage); // scanf(); is how you do an input. You MUST have & behind a variable after a %d!!
    printf("You are %d years old\n", inputage);
    printf("Was yo GPA?\n");
    scanf("%lf", &gpainput); // %lf is for double variables when using scanf() but using printf() it uses %s for variables. Confusing, I know.
    printf("Your GPA is %f\n", gpainput);
    printf("Wos yo name now that ive asked yo fo yo gpa and age\n");
    scanf("%c", namehumaninput); // %c is universal for both
    printf("Really? Yo name is %c?\n", namehumaninput);

我已经导入了stdio和stdlib库，并且正在使用MacOS。