我尝试使用Tuple3将3个Flux对象聚合为1个对象。但是，我仍然卡住了。我在网上搜索，看到可以使用Mono.zip()，但不适用于Flux。

public class OrderService {

    private final AppWebClient appWebClient;

    public Mono<OrderDetailsAggregate> getAggregatedOrderDetails(List<String> orderNoList1,
            List<String> orderNoList2, List<String> orderNoList3) {
        Flux<Map<String, List<String>>> fluxOne = this.appWebClient.getFluxOne(orderNoList1);
        Flux<Map<String, String>> fluxTwo = this.appWebClient.getFluxTwo(orderNoList2);
        Flux<Map<String, List<String>>> fluxThree = this.appWebClient.getFluxThree(orderNoList3);

        return Mono.zip(fluxOne, fluxTwo, fluxThree).map(this::combine); //error here
    }

    private OrderDetailsAggregate combine(
            Tuple3< Flux<Map<String, List<String>>>, Flux<Map<String, String>>, Flux<Map<String, List<String>>> > tuple) {
        return OrderDetailsAggregate.create(tuple.getT1(), tuple.getT2(), tuple.getT3()); 
    }

}

fluxOne、fluxTwo和fluxThree具有不同的数据类型。

订单详细信息聚集类

@Data
@ToString
@AllArgsConstructor(staticName = "create")
public class OrderDetailsAggregate {

    private Flux<Map<String, List<String>>>  fluxOne;
    private Flux<Map<String, String>> fluxTwo;
    private Flux<Map<String, List<String>>> fluxThree;
}

我如何将它们结合起来？
谢谢你。