我目前正在尝试编写一个bash/shell脚本，该脚本从.csv中提取数据，每隔一列反转所有字符串值，并输出到一个新的csv。我有一个脚本，该脚本每隔一列获取数据，但我不确定如何反转这些列中的字符串。
awk 'BEGIN{FS=","} {s=$NF; for (i=1; i<=NF; i+=2) printf ("%s%c", $i, i + 2 <= NF ? "," : "\n") }' input.csv > output.csv
h7wcgrx31#
awk来救援！
awk
$ seq 100 141 | pr -6ats, | awk -F, 'function rev(x) {r=""; for(j=length(x);j;j--) r=r substr(x,j,1); return r} BEGIN {OFS=FS} {for(i=1;i<NF;i+=2) $i=rev($i)}1' 001,101,201,103,401,105 601,107,801,109,011,111 211,113,411,115,611,117 811,119,021,121,221,123 421,125,621,127,821,129 031,131,231,133,431,135 631,137,831,139,041,141
egdjgwm82#
$ cat file abc,def,ghi,klm $ rev file mlk,ihg,fed,cba $ rev file | awk 'BEGIN{FS=OFS=","} NR==FNR{split($0,a); next} {for (i=1; i<=NF; i+=2) $i=a[NF-i+1]} 1' - file cba,def,ihg,klm
2条答案
按热度按时间h7wcgrx31#
awk来救援！egdjgwm82#