已关闭。此问题需要超过focused。当前不接受答案。
**想要改进此问题吗？**更新此问题，使其仅关注editing this post的一个问题。

2天前关闭。
Improve this question
我正在创建一个数字猜谜游戏，但遇到了以下问题（做，while）循环。用户将输入他们的猜测，程序将告诉他们他们的猜测是太高还是太低。如果猜测不在1和100之间，程序将提示一条消息，说只有1和100之间的数字是有效的，并且不会计入他们有限的尝试次数。代码需要使用嵌套循环。
我还没有开始工作的部分是当用户猜测正确的数字，程序打印他们的分数，或者如果他们已经用完或尝试。我如何让打印语句在用户猜测正确答案时打印？

static Scanner sc = new Scanner(System.in);

    public static void main(String[] args) {
        boolean keepPlaying = true;
        System.out.println("Play Guessing Game");
        int tryCount = 0;
        int counter = 9;
        while (keepPlaying) {
            boolean validInput;
            int number, playerGuess;

            number = (int) (Math.random() * 100) + 1;

            System.out.print("\nim thinking of a number between 1 and 100");
            System.out.println();

            do {
                playerGuess = sc.nextInt();

                if ((playerGuess < 1) || (playerGuess > 100)) {
                    System.out.println("Only numbers between 1 and 100   ");
                } else if (number > playerGuess && tryCount < (9)) {
                    System.out.println(" Guess higher " + " you have " + (counter) + " attempts");
                    tryCount++;
                    counter--;
                } else if (number < playerGuess && tryCount < (9)) {
                    System.out.println(" Guess lower " + " you have " + (counter - 1) + " attempts");
                    tryCount++;
                    counter--;
                } else if (number < playerGuess && tryCount == (9)) {
                    System.out.println("Guess lower" + " you have " + (counter - 1) + " attempt ");
                    tryCount++;
                    counter--;
                } else if (number > playerGuess && tryCount == (9)) {
                    System.out.println("Guess higher" + " you have " + (counter - 1) + " attempt ");
                    tryCount++;
                    counter--;
                }

            } while (playerGuess == number);

            {
                if (number == playerGuess) {
                    System.out.println("win");
                }

            }
        }
    }

}