实际上，您希望检查数字是否以0开头，即它们的绝对值是否小于1。在这种情况下，您可以用途：

for i in range(len(a)):
    if (np.abs(a[i]) < 1).all():
        a[i] = 0

给你：

a = np.array([[61.22,92.92,53.0],
             [-0.272,0.2828,-0.737],
             [12.43,-0.732,0.82],
             [52.1,62.12,37.78],
             [0.1,0.67,-0.22],
             [-.09,-0.28,0.22],
             [82.1,11.12,45.78],
             [52.1,0.12,37.78]])

a[np.all(np.abs(a) < 1, axis=1), :] = 0

# a is now:
#
# array([[61.22 , 92.92 , 53.   ],
#       [ 0.   ,  0.   ,  0.   ],
#       [12.43 , -0.732,  0.82 ],
#       [52.1  , 62.12 , 37.78 ],
#       [ 0.   ,  0.   ,  0.   ],
#       [ 0.   ,  0.   ,  0.   ],
#       [82.1  , 11.12 , 45.78 ],
#       [52.1  ,  0.12 , 37.78 ]])

您的问题是，您正在检查if a[i].all()==0:，但您想要的是行中所有小于1的数字的绝对值。

也许你可以这样做：

import numpy as np

a = np.array([[61.22,92.92,53.0],
                 [-0.272,0.2828,-0.737],
                 [12.43,-0.732,0.82],
                 [52.1,62.12,37.78],
                 [0.1,0.67,-0.22],
                 [-.09,-0.28,0.22],
                 [82.1,11.12,45.78],
                 [52.1,0.12,37.78]])

for i in range(len(a)):
   all_zero: bool = True
   
   for j in range(len(a[i])):
        num_str: str = str(a[i][j])
        first_digit: int = int(num_str[1] if num_str[0] == '-' else num_str[0])
        if first_digit == 0:
            all_zero = True
        else:
            all_zero = False
            break
   
   if all_zero:
       for j in range(len(a[i])):
           a[i][j] = 0
    

print(a)

它检查每个数组及其每个元素。如果数组中每个项的第一个实际数字为零，则将数组的每个元素设置为零。

必须将else-0.737舍入为1.0

a[np.all( np.where(np.trunc(a)==0,True,False),axis=1)]=0