我在Django中有一个函数，它使用youtube API根据用户通过用户创建视频对象表单提供的web_url返回video_id，title和thumbnail_url。我这样做的原因是为了让用户更容易上传youtube视频到我的应用。

def get_video_info(pk):
    print('get_video_info called')
    video = Video.objects.get(id=pk)
    web_url = video.web_url

    # Parse the video ID from the URL
    parsed_url = urlparse(web_url)
    query_params = parse_qs(parsed_url.query)
    video_id = query_params["v"][0]

    # Create a YouTube Data API client
    api_key = settings.YOUTUBE_API_KEY
    youtube = build('youtube', 'v3', developerKey=api_key)

    # Call the YouTube API to get the video details
    video_response = youtube.videos().list(
        part='id, snippet',
        id=video_id,
        maxResults=1
    ).execute()

    # Extract the video details from the API response
    video_snippet = video_response['items'][0]['snippet']
    thumbnail_url = video_snippet['thumbnails']['medium']['url']
    title = video_snippet['title']

    return {
        'video_id': video_id,
        'thumbnail_url': thumbnail_url,
        'title': title,
    }

然后我有一个信号函数，它在创建Video对象时触发get_video_info函数，然后用函数的返回值更新Video字段。

@receiver(post_save, sender=Video)
def create_video_info(sender, instance, created, **kwargs):
    print('create signal called')
    if created: # if the instance is being created
        video_id, thumbnail_url, title = get_video_info(instance.pk).values()
        instance.video_id = video_id
        instance.thumbnail_url = thumbnail_url
        instance.title = title
        instance.save()

我的问题是，当我试图创建一个类似的信号，当视频对象正在更新，我得到了一个无限递归循环。2任何想法，如何解决这个问题将不胜感激，谢谢！
这是我之前尝试的信号：

@receiver([post_save, post_delete], sender=Video)
def update_video_info(sender, instance, **kwargs):
    print('update signal called')
    if hasattr(instance, 'pk') and instance.pk:
        video_id, thumbnail_url, title = get_video_info(instance.pk).values()
        instance.video_id = video_id
        instance.thumbnail_url = thumbnail_url
        instance.title = title
        instance.save()