不确定我是否理解正确，你是说如果有一个空对象而不是{}，它在这种情况下失败，如果是这样，那么你可以在你的条件下使用null safe operator，比如i=> i?.id

var myArray = [
 {id:1, name:"bob"},
 {id:2, name:"dan"},
 {},
]

// grab the Array item which matchs the id "6"
var item = myArray.find(i => i.id === 6);

// print
console.log("When item is empty object",item?.name);
var myArray = [
 {id:1, name:"bob"},
 {id:2, name:"dan"},
 null,
]
// grab the Array item which matchs the id "6"
var item2 = myArray.find(item => item?.id === 6);
console.log("When item is null",item?.name);

请使用可选链接（？.）
https://stackoverflow.com/a/63498539/10562084

var myArray = [
 {id:1, name:"bob"},
 {id:2, name:"dan"},
 {},
 null,
]

// grab the Array item which matchs the id "6"
var item = myArray.find(item => item?.id === 6);

// print
console.log(item?.name);

在记录item.name之前，必须检查该项目是否存在。

// print
 if (item) {
   console.log(item.name);
 } else {
   console.log('No item was found');
 }

这里，是你的问题的简单解决方案。

var myArray = [
     {id:1, name:"bob"},
     {id:2, name:"dan"},
     {},
    ];

//在数组中查找

var item = myArray.find(item => {if(item.id) { return item.id === 2}});

//日志名称

console.log(item?.name);