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Does clock measure sleep i.e. suspended threads?（1个答案）
昨天关门了。
我希望下面的代码输出执行代码所花费的时间大约为5秒。

#include <stdio.h>
#include <time.h>
#include <unistd.h>
 
int main() {
    clock_t start, end;

    /* Store start time here */
    start = clock();
    
    /* Do 5 seconds of work */
    sleep(5);

    /* program logic ends here */
    end = clock();

    printf("start: %f\n", (double)start);
    printf("end: %f\n", (double)end);
    
    /* Get the time taken by program to execute in seconds */
    double duration = ((double)end - start)/CLOCKS_PER_SEC;
     
    printf("duration: %f, CPS: %li\n", duration, CLOCKS_PER_SEC);

    printf("Time taken to execute in seconds : %f\n", duration);
    return 0;
}

但我得到了以下输出：

start: 1097.000000
end: 1144.000000
duration: 0.000047, CPS: 1000000
Time taken to execute in seconds : 0.000047

有人能解释一下为什么Time taken to execute in seconds不是5秒吗？