我必须将输入作为JSON，然后使用XSLT将其转换为另一个JSON。
输入JSON：

{
  "members": [
    {
      "name": "Molecule Man1",
      "age": 29,
      "secretIdentity": "Dan Jukes"
    },
    {
      "name": "Molecule Man2",
      "age": 30,
      "secretIdentity": "Martin"
    }
  ]
}

我想将上面的JSON转换为如下所示：

{
   "resourceType": "Test",
   "type": {
      "name": "Member"
   },
   "displayName": "Molecule Man",
   "attributes": {
      "test": [
         {
            "value": "29"
         }
      ],
      "testing": [
         {
            "value": "Dan Jukes"
         }
      ]
   }
}

我尝试了以下代码，但无法获得所需的输出JSON。我收到错误SERE 0023 JSON序列化：无法处理长度为2的序列，并且还获得错误saxon：数组未被识别为****Saxon指令。Saxon扩展要求Saxon-PE或更高版本，同时尝试实现saxon::array.
我使用了Saxon HE（12.0）依赖项。

Java代码

package com.practice;

import net.sf.saxon.s9api.*;
import javax.xml.transform.stream.StreamSource;

import java.io.File;

import java.io.FileInputStream;

import java.io.FileNotFoundException;

import java.io.InputStreamReader;

import java.nio.charset.StandardCharsets;

public class JsonToXsltToJson {
    public static void main(String[] args) throws FileNotFoundException, SaxonApiException {
        Processor processor = new Processor(false);
        TransformJson(processor);
    }

    static void TransformJson(Processor processor) throws 
 FileNotFoundException, SaxonApiException {
       
        JsonBuilder jsonBuilder = processor.newJsonBuilder();
        XdmValue input = jsonBuilder.parseJson(new InputStreamReader(new FileInputStream("input.json"), StandardCharsets.UTF_8));
        XsltCompiler xsltCompiler = processor.newXsltCompiler();
        XsltExecutable xsltExecutable = xsltCompiler.compile(new StreamSource(new File("jsonTransform.xsl")));
        Xslt30Transformer xslt30Transformer = xsltExecutable.load30();
        xslt30Transformer.applyTemplates(input, xslt30Transformer.newSerializer(System.out));

    }
}

sample.xsl：

<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
                version="3.0"
                xmlns:xs="http://www.w3.org/2001/XMLSchema"
                xmlns:map="http://www.w3.org/2005/xpath-functions/map"
                xmlns:mf="http://example.com/mf" 
                exclude-result-prefixes="#all">

    <xsl:param name="nodes" as="map(*)*"/>

    <xsl:template name="init">
        <xsl:apply-templates select="($nodes)"/>
    </xsl:template>

    <xsl:template  match=".">
        <xsl:map>
            <xsl:map-entry key="'resourceType'" select="'Test'"/>
            <xsl:map-entry key="'type'">
            <xsl:map-entry key="'name'" select="'Member'"/>
            </xsl:map-entry>
            <xsl:map-entry key="'displayName'" select= "?members?1?name"/>
            <xsl:map-entry key="'attributes'">
            <xsl:map-entry key="'age'">
            <xsl:map-entry key="'value'" select="?members?1?age"/>
            </xsl:map-entry>
                <xsl:map-entry key="'secretIdentity'">
                    <xsl:map-entry key="'value'" select="?members?1?secretIdentity"/>
                </xsl:map-entry>
            </xsl:map-entry>
        </xsl:map>
    </xsl:template>
    <xsl:output method="json" indent="yes"/>
</xsl:stylesheet>