stoi函数使程序崩溃并显示错误消息
"****@****:~> g++ -std=c++0x m1.cpp stimulation.h stims.h Task.h exoskeleton.h ARAIG_Sensors.h Profile.h
ARAIG_Sensors.h:1:9: warning: #pragma once in main file [enabled by default]
Profile.h:1:9: warning: #pragma once in main file [enabled by default]
*****@****:~> a.out StimulationConfig.csv TaskConfiguration.csv SampleProfileConfig.csv SampleOutput.txt
First : a.out
Second : StimulationConfig.csv
terminate called after throwing an instance of 'std::invalid_argument'
what(): stoi
Aborted
我不知道为什么,有一个示例被传递到函数中,但仍然返回一个错误。有人能帮我解决这个问题吗?
#pragma once
#include <string>
#include <vector>
#include "Task.h"
#include <ostream>
#include "ARAIG_Sensors.h"
namespace m1
{
class Profile
{
ARAIG_Sensors araig;
std::vector<Task> ToRun;
std::vector<Task> Completed;
std::string studentFN;
std::string studentLN;
std::string studentSN;
std::string flightFN;
std::string flightLN;
std::string flightEN;
std::ostream& os;
struct calibration {
int Max;
int Min;
};
calibration cal;
public:
Profile(std::string fn, std::ostream& o, ARAIG_Sensors& a) : os(o)
{
araig = a;
//parsing student
std::ifstream infile(fn);
std::string line;
std::getline(infile, line);
int f = line.find_first_of(",");
studentFN = line.substr(0, f);
line = line.substr(f + 1);
f = line.find_first_of(",");
studentLN = line.substr(0, f);
studentSN = line.substr(f + 1);
//parsing flight
std::getline(infile, line);
f = line.find_first_of(",");
flightFN = line.substr(0, f);
line = line.substr(f + 1);
f = line.find_first_of(",");
flightLN = line.substr(0, f);
flightEN = line.substr(f + 1);
//parsing calibration
std::getline(infile, line);
f = line.find_first_of(",");
cal.Min = stoi(line.substr(0, f));
std::cout << cal.Min << std::endl;
line = line.substr(f + 1);
cal.Max = stoi(line);
std::list<Task> temp = araig.gettasks();
while (std::getline(infile, line))
{
for (std::list<Task>::iterator i = temp.begin(); i != temp.end(); i++)
{
if ((*i).getName() == line)
{
ToRun.push_back(*i);
break;
}
}
}
}
void displayToRun()
{
for (std::vector<Task>::iterator i = ToRun.begin(); i != ToRun.end(); i++)
{
(*i).execute(os);
}
}
void displayCompleted()
{
for (std::vector<Task>::iterator i = Completed.begin(); i != Completed.end(); i++)
{
(*i).execute(os);
}
}
void displayNext()
{
std::vector<Task>::iterator i = ToRun.begin();
(*i).execute(os);
}
void displayLast()
{
std::vector<Task>::iterator i = Completed.end();
(*i).execute(os);
}
void Run()
{
//excute next Task and move Task to Completed
std::vector<Task>::iterator i = ToRun.begin();
Task t = *i;
t.execute(os);
ToRun.erase(i);
Completed.push_back(t);
}
};
}
2条答案
按热度按时间4si2a6ki1#
这意味着您给了
std::stoi()
错误的输入,因此它抛出了一个您没有捕获的std::invalid_argument
异常。std::stoi, std::stol, std::stoll:
例外情况
std::invalid_argument
如果无法执行转换std::out_of_range
,如果转换后的值超出结果类型的范围,或者基础函数(std::strtol
或std::strtoll
)将errno
设置为ERANGE
。std::terminate
当异常处理由于以下原因失败时,C++运行时将调用std::terminate():
1)抛出异常但未捕获(在这种情况下是否进行堆栈展开由实现定义)
你需要仔细检查你要转换成整数的输入字符串值。它们不代表整数。
hmae6n7t2#
您可以使用stroi代替stoi(stroi有一个更健壮的错误处理例程)。