java 扫描仪不接受用户输入?[已关闭]

r1zhe5dt  于 2023-03-21  发布在  Java
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我正在做一个小的文本冒险,基于我在网上看到的教程,每次我输入1,2或3,它都会一直循环回到我的无效命令。这是假设,只有当用户输入这3个数字中的任何一个时,它才会启动。有什么想法吗?我错过了什么?

String input = in.nextLine();
      if (input.equals(1)) {
          int damageDealt = rand.nextInt(attackDamage);
          int damageTaken = rand.nextInt(enemyAttackDamage);
          
          enemyHealth -= damageDealt;
          health -= damageTaken;
          
          System.out.println ("\t> You strike the " + enemy + " for " + damageDealt + " damage. ");
          System.out.println ("\t> You receive " + damageTaken + " in retaliation! ");
          
          if(health < 1) {
              System.out.println ("\t> You have taken too much damage, you are too weak to go on!");
              break;
              
          }
          
      }
      else if (input.equals(2)) {
          if(numHealthPots > 0) {
            health += healthPotionHealAmount;
            numHealthPots--;
            System.out.println ("\t You drink a health potion, healing yourself for " + healthPotionHealAmount +"." + "\n\t> You now have " + health + " HP. " + "\n\t> You have " + numHealthPots + " health potions left. \n");  
          }
          else {
              System.out.println("\t You have no health potions left! Defeat an enemy for a chance to get one. ");
          }
      }
      else if (input.equals(3)) {
          System.out.println("\tYou run away from the " + enemy + "!");
          continue GAME;
      }
      else {
          System.out.println("\tInvalid command.");
      }
   }
   
   if(health <1 ) {
       System.out.println("\tYou are too weak to go on.");
       break;
   }

我检查输入的值是否有任何错误,即数字后面的任何点,但什么也没有出现。

sshcrbum

sshcrbum1#

如果你想用同样的方法比较String和int,可以使用这个

if(input.equals(Integer.toString(1))){
        // Your code here      
   }

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