我的问题是，我不知道如何检查对象的所有值是否为空，这样数据库就不会获得项目的所有详细信息为空。因此，我想将其中至少有一个值的对象保存到mongoose。现在，当我编辑供应商品牌信息时，它总是将空的供应商数据推送到mongoose架构。

const editBrand = asyncHandler(async (requestObject, responseObject) => {
  const id = requestObject.params.id;
  const supplierInfo = {};
  const { name, madeIn } = await Brand.findById(id);
  if (
    name !== requestObject.body.name ||
    madeIn !== requestObject.body.madeIn
  ) {
    requestObject.body.slug = slugify(
      requestObject.body.name + " " + requestObject.body.madeIn
    );
  }
  if (requestObject.body.category) {
    const { id } = await Category.findOne({
      name: requestObject.body.category,
    });
    requestObject.body.category = id;
  }
  if (requestObject.body.supplier) {
    supplierInfo.name = requestObject.body.supplier.name
      ? format(requestObject.body.supplier.name)
      : undefined;
    supplierInfo.phone = requestObject.body.supplier.phone || undefined;
    supplierInfo.email = requestObject.body.supplier.email || undefined;
    supplierInfo.address = requestObject.body.supplier.address || undefined;
  }
  const update = await Brand.findByIdAndUpdate(
    id,
    {
      name: requestObject.body.name || undefined,
      madeIn: requestObject.body.madeIn || undefined,
      slug: requestObject.body.slug || undefined,
      category: requestObject.body.category || undefined,
      manufacturer: requestObject.body.manufacturer || undefined,
      $push: { supplier: supplierInfo || undefined },
    },
    { new: true, runValidators: true }
  );
  if (!update) {
    responseObject
      .status(417)
      .json({ message: "Unable to update record, please try again." });
  } else {
    responseObject.status(200).json(update);
  }
});

请指导我如何实现这一点。