React Native 在typescript中调用接口内部的其他方法

8xiog9wr 于 2023-03-24 发布在 React

关注(0)|答案(2)|浏览(136)

新手在这里打字。
我有用Typescript写的接口和方法。我想在另一个函数中调用另一个函数。我们如何在Typescript中做到这一点。

export interface InterfaceProps {
  someFunction1(): Promise<boolean>;
}

export const someClass: InterfaceProps {
 async someFunction1(): Promise<boolean> {
    someFunction2(); // This is not allowed right now. But how can i acheive this.
 }

 async someFunction2(): Promise<boolean> {
 }
}

react-native

来源：https://stackoverflow.com/questions/75805919/call-each-other-methods-inside-the-interface-in-typescript

2条答案

按热度按时间

qhhrdooz1#

我可以提出以下解决办法：

export interface InterfaceProps {
  someFunction1(): Promise<boolean>;
  someFunction2(): Promise<boolean>;
}

export const someClass1: InterfaceProps = {
 someFunction1: async(): Promise<boolean> => {
    return someClass1.someFunction2() // function call in the someFunction1 and return Promise boolean
 },
 someFunction2: async (): Promise<boolean> => Promise.resolve(true), // Function return Promise boolean
}

// OR

export const someClass2: InterfaceProps = {
 someFunction1: async(): Promise<boolean> => {
    someClass2.someFunction2() // function call in the someFunction1
    return Promise.resolve(true) // return Promise boolean
 },
 someFunction2: async (): Promise<boolean> => Promise.resolve(true), // Function return Promise boolean
}

请注意，我使用箭头功能，我建议你这样做。
Playground

赞(0）回复(0）举报 2023-03-24

nhjlsmyf2#

你得到错误，因为你为someFunction1定义了Promise<boolean>类型返回值，你应该在函数的末尾返回一个promise（布尔类型），你也忘记在InterfaceProps接口中定义someFunction2：

export interface InterfaceProps {
  someFunction1(): Promise<boolean>;
  someFunction2(): Promise<boolean>;
}

export const someClass: InterfaceProps = {
  async someFunction1(): Promise<boolean> {
    return await this.someFunction2();
  },
  async someFunction2(): Promise<boolean> {
    return new Promise(resolve => setTimeout(() => resolve(true), 1000));
  },
};

但是如果你不想返回一些东西并假设为void，那么就像下面这样做：

赞(0）回复(0）举报 2023-03-24

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React Native 在typescript中调用接口内部的其他方法

2条答案

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