我想通过printf在C中多次调用相同的字符串

afdcj2ne 于 2023-03-28 发布在其他

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我正在做哈佛CS50，在第二节C语言课上，老师说%s会自动连续打印每个额外的参数。
好的，这很酷。但是如果我想多次打印第一个字符串呢？

#include <stdio.h>

int main(void) {
   char firstname[5] = "Bruce";
   char lastname[5] = "Wayne";

   printf("Hi, %s!\nI am your virtual butler. I will call you Master %s from now on.\nWelcome to %s Manor!", firstname, lastname);
}

但是，它输出：

Hi, BruceWayne!
I am your virtual butler. I will call you Master Wayne from now on.
Welcome to  q��U Manor!

取代：

Hi, Bruce!
I am your virtual butler. I will call you Master Wayne from now on.
Welcome to Wayne Manor!

我试着在谷歌上搜索，没有找到相关的信息来解决这个问题。
更新#1：
根据建议，我做了修改。

#include <stdio.h>

int main(void) {
   char firstname[] = "Bruce";
   char lastname[] = "Wayne";

   printf("Hi, %s!\nI am your virtual butler. I will call you Master %s from now on.\nWelcome to %s Manor!", firstname, lastname);
}

它输出：

Hi, Bruce!
I am your virtual butler. I will call you Master Wayne from now on.
Welcome to  ���(V Manor!

韦恩庄园的事还没解决
更新#2

printf("Hi, %s!\nI am your virtual butler. I will call you Master %s from now on.\nWelcome to %s Manor!", firstname, lastname, lastname);

按预期工作！

c

来源：https://stackoverflow.com/questions/75850842/i-want-to-the-same-string-multiple-times-in-c-via-printf

1条答案

按热度按时间

cvxl0en21#

问题是这些数组

char firstname[5] = "Bruce";
char lastname[5] = "Wayne";

不包含字符串。您需要扩大数组以包含字符串字面量的终止零字符'\0'，如

char firstname[6] = "Bruce";
char lastname[6]  = "Wayne";

或者允许编译器自己计算数组的大小，如

char firstname[] = "Bruce";
char lastname[]  = "Wayne";

另一个问题是，格式字符串包含三个转换说明符s，但您只提供了两个相应的参数

printf("Hi, %s\nI am your virtual butler. I will call you Master %s from now on.\nWelcome to %s Manor!", firstname, lastname);

你需要写多加一个参数

printf("Hi, %s\nI am your virtual butler. I will call you Master "
       "%s from now on.\nWelcome to %s Manor!", 
       firstname, lastname, lastname);

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我想通过printf在C中多次调用相同的字符串

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