初始查询查找每个feature_id所应用的语言,并将结果放入数组中。我想计算每个区域、每个feature_id、每个版本(新版本和旧版本)中的语言数量。
SELECT
array_length(applied_languages_in_old_version, 1) AS COUNT1,
array_length(applied_languages_in_new_version, 1) AS COUNT2
FROM (
SELECT
t1.feature_id,
t1.territory_type,
t1.territory_category,
(array_agg(DISTINCT t2.language), ', ') AS applied_languages_in_old_version,
(array_agg(DISTINCT t4.language), ', ') AS applied_languages_in_new_verison
FROM kh_bel_territory_2023mar14.kh_bel_territory_2023mar14_territory t1
LEFT OUTER JOIN kh_bel_territory_2023mar14.kh_bel_territory_2023mar14_territory_name t2
ON t1.feature_id = t2.feature_id AND t2.name_type = 'PRIMARY_FOR_LANGUAGE'
JOIN kh_bel_territories_08nov2022.kh_bel_territories_08nov2022_territory t3
ON t1.feature_id = t3.feature_id
LEFT OUTER JOIN kh_bel_territories_08nov2022.kh_bel_territories_08nov2022_territory_name t4
ON t1.feature_id = t4.feature_id AND t4.name_type = 'PRIMARY_FOR_LANGUAGE') a
GROUP BY
t1.feature_id,
t1.territory_type,
t1.territory_category
ORDER BY t1.feature_id;
**结果:**错误:列“t1.feature_id”必须出现在GROUP BY子句中或在聚合函数中使用
1条答案
按热度按时间nukf8bse1#
正如错误消息所述,select中的所有列都必须在
GROUP BY
中或使用聚合函数,我认为您可以使用MAX
,但这可能是对您正在寻找的内容的误解