你可以试试这段代码，也许需要一些注意事项：

from django.core.servers.basehttp import FileWrapper
import mimetypes

def download_image(request, image_id):
    img = ImageModel.objects.get(id=image_id)
    wrapper      = FileWrapper(open(img.file))  # img.file returns full path to the image
    content_type = mimetypes.guess_type(filename)[0]  # Use mimetypes to get file type
    response     = HttpResponse(wrapper,content_type=content_type)  
    response['Content-Length']      = os.path.getsize(img.file)    
    response['Content-Disposition'] = "attachment; filename=%s" %  img.name
    return response

1.我假设在ImageModel中有一个字段.name，用于获取倒数第二行...filename=%s" % img.name中的文件名。
1.在***ImageField***中有一个字段是file，在这里的代码中，我使用img.file来获取文件的路径，您应该为img.YOUR_IMAGE_FIELD.file或任何需要获取图像路径的内容更改该字段

你需要使用Content-Disposition头文件，看看这里：
Generating file to download with Django
Django Serving a Download File

一个基于类的views-type的例子是这样的（我使用python-magic来获取文件的正确内容类型）：

import os
import magic

from django.views.generic import View
from django.http import HttpResponse

from .models import ImageModel

class ImageDownloadView(View):

    def get(self, request, *args, **kwargs):
        image = ImageModel.objects.get(pk=self.kwargs['image_id'])
        image_buffer = open(image.file.path, "rb").read()
        content_type = magic.from_buffer(image_buffer, mime=True)
        response = HttpResponse(image_buffer, content_type=content_type);
        response['Content-Disposition'] = 'attachment; filename="%s"' % os.path.basename(image.file.path)
        return response

这适用于Django 1.10.7，但对于Django 1.7应该没有什么不同

其他两个答案是可以的，但正如许多地方所宣传的那样，出于性能原因，不建议使用Django来提供静态文件。最好使用您的Web服务器（nginx/apache...）来提供它。
您不需要额外的视图来提供静态文件。只需在模板中呈现指向该文件的链接：

<a href="{{object.image.url}} download">Download this image!</a>

其中object是ImageModel的示例。
参见django.db.models.fields.files.FieldFile.url
如果你真的想在像www.example.com/image/download/1这样的URL中有一个视图，你可以简单地写一个视图，重定向到从字段中获得的图像URL。

这段代码在新版本的Django中运行良好：

import mimetypes

def download_image(request, id):
    img = ImageModel.objects.get(id=id)
    wrapper = img.field_name
    content_type = mimetypes.guess_type(img.field_name.name)[0]
    response = HttpResponse(wrapper, content_type=content_type)
    response['Content-Length'] = img.field_name.size
    response['Content-Disposition'] = f"attachment; filename={img.field_name.name}"
    return response

将field_name更改为字段。字段必须是ImageField或FileField。

这里是您的跨浏览器安全下载的文件包含任何字符类型

# Even better as it works in any browser (mobile and desktop)
def safe_name(file_name):
    """
    Generates a safe file name, even those containing characters like ? and &
    And your Kanji and Cyrillics are supported! 
    """
    u_file_name = file_name.encode('utf-8')
    s_file_name = re.sub('[\x00-\xFF]', lambda c: '%%%02x' % ord(c.group(0)), u_file_name)
    return s_file_name

# Handled by url(r'^/image/download/(\d+)/.+$
def safe_download_image(request, image_id):
    """ 
    Safely downloads the file because the filename is part of the URL
    """
    img = ImageModel.objects.get(id=image_id)
    wrapper      = FileWrapper(open(img.file))  # img.file returns full path to the image
    content_type = mimetypes.guess_type(filename)[0]  # Use mimetypes to get file type
    response     = HttpResponse(wrapper,content_type=content_type)  
    response['Content-Length']      = os.path.getsize(img.file)     
    # This works for most browsers, but IE will complain sometimes
    response['Content-Disposition'] = "attachment;"
    return response

def download_image(request, image_id):
    img = ImageModel.objects.get(id=image_id)
    redirect_do = safe_name(img.name)
    return HttpResponseRedirect('/image/download/' + img_id + '/' + redirect_to)

它不起作用。我做了这样的事情：

wrapper = FileWrapper(img.file)  # img.file returns full path to the image
content_type = mimetypes.guess_type(str(img.file))[0]  # Use mimetypes to get file type
response = HttpResponse(wrapper, content_type=content_type)
response['Content-Length'] = os.path.getsize(str(img.file))
response['Content-Disposition'] = "attachment; filename=%s" % img.name

其中img指向我的ImageField字段。文件已下载，但我无法打开它。xUbuntu图像查看器会显示“Not a JPEG file. starts with 0x89 0x50”