我有三个列表，我想用它们建立一个字典：
a = [a,b,c] b = [1,2,3] c = [4,5,6]
我希望有：
{'a':1,4, 'b':2,5, 'c':3,6}
我现在能做的就是：
{'a':1,'b':2, 'c':3}
我该怎么办？
5kgi1eie1#
你可以试试这个：
a = ["a","b","c"] b = [1,2,3] c = [4,5,6] new_dict = {i:[j, k] for i, j, k in zip(a, b, c)}
输出：
{'b': [2, 5], 'c': [3, 6], 'a': [1, 4]}
如果你真的想要一个排序后的结果，你可以试试这个：
from collections import OrderedDict d = OrderedDict() for i, j, k in zip(a, b, c): d[i] = [j, k]
现在，您有了一个键按字母顺序排序的OrderedDict对象。
11dmarpk2#
检查这个：how to zip two lists into new one我建议首先压缩B和c列表，然后再次使用zip将它们Map到字典中：
a = ['a','b','c'] b = [1,2,3] c = [4,5,6] vals = zip(b,c) d = dict(zip(a,vals)) print(d)
lmyy7pcs3#
a = ['a','b','c'] b = [1,2,3] c = [4,5,6] result = { k:v for k,*v in zip(a,b,c)}
结果
print(result)
cld4siwp4#
Promotion_or_Not = "Yes","Yes","No","Yes","Yes","Yes","Yes","No","Yes","No" Nopay_leave_or_not ="No","No","Yes","Yes","No","Yes","Yes","No","Yes","No" Last_year_evaluation = "Good","Bad","Moderate","Good","Moderate","Moderate","Good","Bad","Good","Moderate" mydict = {'Promotion_or_Not': [Promotion_or_Not],'Nopay_leave_or_not': [Nopay_leave_or_not], 'Last_year_evaluation':[Last_year_evaluation] } print(mydict)
4条答案
按热度按时间5kgi1eie1#
你可以试试这个：
输出：
如果你真的想要一个排序后的结果，你可以试试这个：
现在，您有了一个键按字母顺序排序的OrderedDict对象。
11dmarpk2#
检查这个：how to zip two lists into new one我建议首先压缩B和c列表，然后再次使用zip将它们Map到字典中：
lmyy7pcs3#
结果
cld4siwp4#