正如一位评论者所说，您可以使用functools.partial来存储函数，以便稍后进行计算。
下面是一个完整的例子：

import functools

def function1(arg1, arg2):
    print("function1: ", arg1, arg2)

dictionary = {
    "example1": functools.partial(function1, "arg1", "arg2"),
}

dictionary["example1"]()
# prints: function1:  arg1 arg2

partial按照注解工作。但是，请参见下面的输出。
又名：Ninja-ed by Ben

from functools import partial

def this(in_str):
    print(f'{in_str}')
    
def that(in_str, in_key=''):
    print(f'{in_str} {in_key}')
    
foo = {'example_1': [partial(this, 'why'), partial(that,'are',in_key='you')],
       'example_2': [partial(this, 'doing'), partial(that,'this')],
       }

for key, val in foo.items():
    for your_func in val:
        your_func()

输出：

why
are you
doing
this

避免对函数对象求值

为了避免计算函数，你必须传递函数本身。有很多方法可以做到这一点，例如：

e = "something"

func = lambda: print(e)

func()

e = "another thing"

func()

输出：

something
another thing

如果你想使用字典，它的工作方式如下：

dictionary = {"some_func": lambda: function1(argument)}
dictionary["some_func"]()  # argument is is passed to function1, changeable after the declaration

正如答案中已经提到的，你也可以使用functools来实现这一点。

简单介绍参数和函数

如果你只是想存储函数定义，以便以后用任意参数调用：

def some_func(*args, **kwargs):
    """
    args is a tuple of type tuple[Any,...],
    kwargs is a dict of type dict[str, Any]
    """
    for arg in args:
        # do something with your positional args
        print(arg)

dictionary = {"some_func": some_func} # pass the function like so

dictionary["some_func"]("some_arg")

输出：

some_arg