SQL Server Counts by date and status with intermittent data

x8diyxa7 于 2023-04-10 发布在其他

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I would like to count the number of objects (lightbulbs, scheduled jobs, customer billing status) that are in a specific status by date. However, the data is intermittent. Objects may or may not have a row on a specific date.

Not a simple GROUP BY solution. The requirement for number of objects "in a specific status" depends on previous rows.

In the minimum problem to solve example below, on 03-01 a GROUP BY would result in "1 on and 1 off". On 03-02 only a single object is represented. A GROUP BY showing 03-02 results would be "1 on and 0 off". The correct answer for total objects by status on 03-02 is "2 on and 1 off" because it must include the objects with rows on 03-01.

A minimum problem to solve is here

SET NOCOUNT ON
-->>-- minimum problem to solve  -- count by status for a specific day
IF OBJECT_ID('tempdb..#d') IS NOT NULL DROP TABLE #d
CREATE TABLE #d (ndx SMALLINT IDENTITY(1,1), id TINYINT, dt DATE, status CHAR(10) )

INSERT INTO #d (id, dt, status)
VALUES
  ( 1, '20230301' , 'on'        )
, ( 3, '20230301' , 'off'       )
, ( 2, '20230302' , 'on'        )
, ( 3, '20230303' , 'off'       )
, ( 3, '20230305' , 'on'        )
, ( 1, '20230308' , 'off'       )
, ( 2, '20230308' , 'off'       )
, ( 1, '20230310' , 'off'       )
, ( 2, '20230311' , 'off'       )
, ( 1, '20230312' , 'off'       )
, ( 3, '20230312' , 'off'       )
, ( 2, '20230313' , 'on'        )
, ( 1, '20230314' , 'on'        )
, ( 3, '20230314' , 'off'       )
, ( 3, '20230316' , 'off'       )
, ( 2, '20230320' , 'on'        )
, ( 1, '20230321' , 'off'       )

SELECT * FROM #d d ORDER BY id, dt

IF OBJECT_ID('tempdb..#c') IS NOT NULL DROP TABLE #c
CREATE TABLE #c ( calendardt DATE )
INSERT INTO #c(calendardt)
VALUES
  ('2023-03-01 '), ('2023-03-02 '), ('2023-03-03 '), ('2023-03-04 '), ('2023-03-05 ')
, ('2023-03-06 '), ('2023-03-07 '), ('2023-03-08 '), ('2023-03-09 '), ('2023-03-10 ')
, ('2023-03-11 '), ('2023-03-12 '), ('2023-03-13 '), ('2023-03-14 '), ('2023-03-15 ')
, ('2023-03-16 '), ('2023-03-17 '), ('2023-03-18 '), ('2023-03-19 '), ('2023-03-20 ')
, ('2023-03-21 '), ('2023-03-22 '), ('2023-03-23 '), ('2023-03-24 '), ('2023-03-25 ')

SELECT * FROM #c UNION ALL SELECT * FROM #c ORDER BY calendardt

SELECT *
FROM #c c
LEFT JOIN #d d ON d.dt = c.calendardt
ORDER BY c.calendardt, d.id

The expected result should look like this

-->>-- expected result
calendardt  [status]    [count]
2023-03-01  on          1
2023-03-01  off         1
2023-03-02  on          2
2023-03-02  off         1
2023-03-03  on          2
2023-03-03  off         1
2023-03-04  on          2
2023-03-04  off         1
2023-03-05  on          3
2023-03-05  off         0
2023-03-06  on          3
2023-03-06  off         0
2023-03-07  on          3
2023-03-07  off         0
2023-03-08  on          1
2023-03-08  off         2
2023-03-09  on          1
2023-03-09  off         2
2023-03-10  on          1
2023-03-10  off         2
2023-03-11  on          1
2023-03-11  off         2
2023-03-12  on          1
2023-03-12  off         2
2023-03-13  on          0
2023-03-13  off         3
2023-03-14  on          0
2023-03-14  off         3
2023-03-15  on          0
2023-03-15  off         3
2023-03-16  on          0
2023-03-16  off         3

I do not have an attempt. I am able to track changes to the data on a per day basis. I can capture the first date the object entered a new status and calculate how long it has been in that status. But I am not able calculate the totals by date and status.

Any help counting by date and status would be appreciated.

sql-server

来源：https://stackoverflow.com/questions/75952585/counts-by-date-and-status-with-intermittent-data

2条答案

按热度按时间

yfwxisqw1#

with changes as (
  select id, dt, status 
  from (select id, dt, status, 
               case when lag(status) over (partition by id order by dt)  = status 
               then 0 else 1 end chg 
        from #d) t
  where chg = 1),
cal as (
  select calendardt dt, id from #c cross join (select distinct id from #d) t),
joined as (
  select cal.dt, cal.id,
         last_value(status) ignore nulls 
         over (partition by cal.id order by cal.dt) status 
  from cal left join changes d on cal.dt = d.dt and d.id = cal.id)
select * --dt, stat_on, stat_off 
from joined pivot (count(id) for status in ([on], [off])) piv
order by dt

SQL Server dbfiddle

Initially I made solution in Oracle, dbfiddle is here . My knowledge of SQL Server is very limited and I can test it only in dbfiddle, but it returns expected values (until 13 April, but I think it should be 1 ON, because id=2 is ON).

The idea is to first eliminate rows which do not change anything (status off->off for example), then join with calendar and cross join with all ids. This way we have rows for each day and id. Then last_value fills missing data. And we can aggregate.

赞(0）回复(0）举报 2023-04-10

hwamh0ep2#

On/off table is missing

..

CREATE TABLE #on_off (status varchar(3));

INSERT INTO #on_off (status)
VALUES
  ('on'), ('off');

SELECT c.calendardt, c.status, count(d.id) n
FROM (
  select c.*, f.*
  from #c c
  cross join #on_off f
) c
LEFT JOIN #d d ON d.dt = c.calendardt and d.status = c.status
GROUP BY c.calendardt, c.status
ORDER BY c.calendardt, c.status

db<>fiddle

赞(0）回复(0）举报 2023-04-10

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SQL Server Counts by date and status with intermittent data

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