如何在Groovy中根据数字按字母数字中定义的字段对类列表进行排序？

goucqfw6 于 2023-04-19 发布在其他

关注(0)|答案(1)|浏览(144)

我需要检查具体排序。有类列表：

[
no = '1'
field = 'FEE_HIG_R_test1234_2',

no = '2'
field = 'FEE_HIG_R_test1234_11',

no = '3'
field = 'FEE_HIG_R_test1234_10',

no = '4'
field = 'FEE_HIG_R_test1234_1',

no = '5'
field = '06633-146944-0000036012',

no = '6'
field = '06633-155867-0000051910',

no = '7'
field = '06687-250844-00002544203'
]

我必须根据数字按字母数字字段进行排序，并得到如下结果：

[
no = '5'
field = '06633-146944-0000036012',

no = '6'
field = '06633-155867-0000051910',

no = '7'
field = '06687-250844-00002544203',

no = '4'
field = 'FEE_HIG_R_test1234_1',

no = '1'
field = 'FEE_HIG_R_test1234_2',

no = '3'
field = 'FEE_HIG_R_test1234_10',

no = '2'
field = 'FEE_HIG_R_test1234_11'
]

我尝试了：result.sort{ a，B -〉（（（a.field =~ /\d+/）[-1] as Integer）〈=〉（（b.field =~ /\d+/）[-1] as Integer）））}
但结果是

[
no = '4'
field = 'FEE_HIG_R_test1234_1',

no = '1'
field = 'FEE_HIG_R_test1234_2',

no = '3'
field = 'FEE_HIG_R_test1234_10',

no = '2'
field = 'FEE_HIG_R_test1234_11',

no = '5'
field = '06633-146944-0000036012',

no = '6'
field = '06633-155867-0000051910',

no = '7'
field = '06687-250844-00002544203'
]

有人能帮忙吗？

groovy

来源：https://stackoverflow.com/questions/75983857/how-to-sort-a-list-of-classes-by-defined-field-in-alphanumeric-based-on-numbers

1条答案

按热度按时间

nbnkbykc1#

类似这样的一行代码：

def data = [
  'FEE_HIG_R_test1234_2',
  '06687-250844-00002544204',
  '06687-250844-00002544203',
  '06687-250844-00002544202',
  'FEE_HIG_R_test1234_1',
  '06633-146944-0000036012',
  '06633-155867-0000051910',
  'FEE_HIG_R_test1234_11',
  'FEE_HIG_R_test1234_10',
]

def result = data.sort{ 
   it ==~ /\d+-\d+-\d+/ 
      ? it.replaceAll( '-', '' ).toBigDecimal() 
      : 10000000000000000000000 + ( it =~ /\d+/ )[ -1 ].toInteger() 
}

assert result.join( '\n' ) == '''\
06633-146944-0000036012
06633-155867-0000051910
06687-250844-00002544202
06687-250844-00002544203
06687-250844-00002544204
FEE_HIG_R_test1234_1
FEE_HIG_R_test1234_2
FEE_HIG_R_test1234_10
FEE_HIG_R_test1234_11'''

需要1000000... +将字符串中较小的数字（如FEE_HIG_R_test1234_1）进一步向右推。

赞(0）回复(0）举报 2023-04-19

我来回答

如何在Groovy中根据数字按字母数字中定义的字段对类列表进行排序？

1条答案

相关问题

热门标签

最新问答