编辑：我的应用是多线程的

假设我有一台服务器

int main()
{
   resolveAddrandPort(hostname, port); // Custom function
   
   SOCKET listening_socket = socket(/* args... */);   // Creates a socket.
   bind(listening_socket, /* args... */);             // Binds the socket to the address and port provided above.

   listen(listening_socket, default_backlog);         // Places the socket in a mode where it can accept any requests.

   add_handlers(10); // Custom function that adds 10 handlers which each run on different threads and can handle requests concurrently (using the same socket[=listening_socket]).

   while(is_recieving_requests)
   {
       SOCKET client_socket = accept(listening_socket, /* args... */);
       handle_request( // Custom function
            find_available_handler(), // Custom function that finds among the 10 handlers which of them is currently free and not handling any requests to handle this request.
            client_socket
       ); 

       clean_up(); // Custom function that cleans up after finishing with the request.
   }

   server_clean_up(); // Cleans up after the server.
}

我用winsock创建服务器
在有关listen的文档中，您可以提供一个backlog来确定有多少请求可以挂起。
现在这可能是愚蠢的，但我假设一个socket不能并发处理多个请求。如果是这样，我认为我必须创建多个listening_socket才能并发处理它。
如果我错了，请纠正我，谢谢你的耐心。