我有一个JSON文件，它多次包含"threatLevel" : (an integer)。我grep JSON，看看它是否包含一个threatLevel，它匹配我的$THREAT_LEVEL变量中的任何东西，最多10（包括）。
我有下面的条件逻辑流，它在很大程度上完成了这项工作。

#!/bin/bash

FILE="${CI_PROJECT_DIR}/iq.results.json"

if [ -z ${THREAT_LEVEL+x} ]; then # Checks if THREAT_LEVEL is unset. If unset, no checks will be made.
    echo "THREAT_LEVEL is unset. The job will ignore checking the results of $FILE.";
    exit 0
elif ! [[ $THREAT_LEVEL =~ ^[0-9]+$ ]]; then # Checks that the THREAT_LEVEL is only a positive integer.
    echo "Error - Invalid THREAT_LEVEL: THREAT_LEVEL must be a positive integer. It is currently set to $THREAT_LEVEL."
    exit 1
elif [ "$THREAT_LEVEL" -lt 1 ] || [ "$THREAT_LEVEL" -gt 10 ]; then # Checks that the THREAT_LEVEL is only between 1 and 10.
    echo "Error - Invalid THREAT_LEVEL: THREAT_LEVEL must be between 1 and 10. It is currently set to $THREAT_LEVEL."
    exit 1
else
    echo "THREAT_LEVEL is currently set to $THREAT_LEVEL"
    if [ "$THREAT_LEVEL" -lt 10 ]; then # If the THREAT_LEVEL is less than 10, grep for anything between THREAT_LEVEL and 10 inclusive.
        if grep -q -E '"threatLevel" : (['"$THREAT_LEVEL"'-9]|10)' "$FILE"; then
            echo "Detected dependencies with Threat Level of $THREAT_LEVEL or above in $FILE. Failing job.";
            exit 1
        else   
            echo "No dependencies with Threat Level of $THREAT_LEVEL or above detected in $FILE. Job allowed to pass";
            exit 0
        fi
    else
        if grep -q -E '"threatLevel" : 10' "$FILE"; then # Else THREAT_LEVEL must be 10. Grep for 10.
            echo "Detected dependencies with Threat Level of 10 in $FILE. Failing job.";
            exit 1
        else   
            echo "No dependencies with Threat Level of 10 or above detected in $FILE. Job allowed to pass.";
            exit 0
        fi
    fi
fi

我觉得这两个elif语句可以结合起来。
第一个elif只检查变量是否是正整数，它不关心它是否大于10，它可以是1000，它不能是字符串或负数或小数等。
第二个elif是检查它福尔斯1-10之间（包括1和10）。
有没有一个解决方案同时满足这两个标准？