如何在Django测试中发送命令行输入响应

ulydmbyx 于 2023-04-22 发布在 Go

关注(0)|答案(2)|浏览(96)

我有一个Django管理命令，它将要求命令行输入（y/n），我现在正在为此编写一个测试。
目前，当我运行测试时（就像现在一样），测试将停止并等待y/n输入。但是我如何编写/更新我的测试，以便我可以向call_command函数发送y/n响应？
作为参考，我的管理命令代码是（已删除导入-但完整代码位于：https://github.com/DigitalCampus/django-oppia/blob/master/oppia/management/commands/remove_duplicate_trackers.py）：

class Command(BaseCommand):
    help = _(u"Removes any duplicate trackers based on UUID")

    def handle(self, *args, **options):
        """
        Remove page/media/quiz trackers with no UUID
        """
        result = Tracker.objects.filter(Q(type='page')
                                        | Q(type='quiz')
                                        | Q(type='media'),
                                        uuid=None).delete()
        print(_(u"\n\n%d trackers removed that had no UUID\n" % result[0]))

        """
        Remove proper duplicate trackers - using min id
        """
        trackers = Tracker.objects.filter(Q(type='page')
                                          | Q(type='quiz')
                                          | Q(type='media')) \
            .values('uuid') \
            .annotate(dcount=Count('uuid')) \
            .filter(dcount__gte=2)

        for index, tracker in enumerate(trackers):
            print("%d/%d" % (index, trackers.count()))
            exclude = Tracker.objects.filter(uuid=tracker['uuid']) \
                .aggregate(min_id=Min('id'))
            deleted = Tracker.objects.filter(uuid=tracker['uuid']) \
                .exclude(id=exclude['min_id']).delete()
            print(_(u"%d duplicate tracker(s) removed for UUID %s based on \
                   min id" % (deleted[0], tracker['uuid'])))

        """
        Remember to run summary cron from start
        """
        if result[0] + trackers.count() > 0:
            print(_(u"Since duplicates have been found and removed, you \
                    should now run `update_summaries` to ensure the \
                    dashboard graphs are accurate."))
            accept = input(_(u"Would you like to run `update_summaries` \
                                now? [Yes/No]"))
            if accept == 'y':
                call_command('update_summaries', fromstart=True)

我的测试代码是：

def test_remove_with_duplicates(self):
    Tracker.objects.create(
        user_id=1,
        course_id = 1,
        type = "page",
        completed = True,
        time_taken = 280,
        activity_title = "{\"en\": \"Calculating the uptake of antenatal care services\"}",
        section_title = "{\"en\": \"Planning Antenatal Care\"}",
        uuid = "835713f3-b85e-4960-9cdf-128f04014178")
    out = StringIO()
    tracker_count_start = Tracker.objects.all().count()

    call_command('remove_duplicate_trackers', stdout=out)

    tracker_count_end = Tracker.objects.all().count()
    self.assertEqual(tracker_count_start-1, tracker_count_end)

任何帮助非常感谢，如果你需要任何额外的信息/代码，只是让我知道，谢谢。

编辑我尝试了@xyres的建议来添加'interactive=False'，但我得到了一个类型错误：

TypeError: Unknown option(s) for remove_duplicate_trackers command: interactive. Valid options are: force_color, help, no_color, pythonpath, settings, skip_checks, stderr, stdout, traceback, verbosity, version

然后，我也尝试使用'skip_checks=True'，但这仍然使测试挂起等待命令行输入

django

来源：https://stackoverflow.com/questions/59382486/how-to-send-command-line-input-responses-in-django-tests

2条答案

按热度按时间

k2arahey1#

我喜欢使用mock.patch来处理这类事情。

from django.core.management import BaseCommand

class Command(BaseCommand):

    def handle(self, *args, **options):
        accept = input("Would you like to run `update_summaries` now? [Yes/No]")
        if accept == 'y':
            self.stdout.write("Updating Summaries!")
            return
        self.stdout.write("Not updating Summaries...")

接下来是TestCase。我喜欢使用调用 Package 器来整合打补丁的逻辑，并允许测试不同的选项等。

from io import StringIO

from unittest import mock

from django.core.management import call_command

from django.test import TestCase

class UpdateTestCase(TestCase):

    @mock.patch("my_app.management.commands.update.input")
    def _call_wrapper(self, response_value, mock_input=None):
        def input_response(message):
            return response_value
        mock_input.side_effect = input_response
        out = StringIO()
        call_command('update', stdout=out)
        return out.getvalue().rstrip()

    def test_yes(self):
        """Test update command with "y" response
        """
        self.assertEqual("Updating Summaries!", self._call_wrapper('y'))

    def test_no(self):
        """Test update command with "n" response
        """
        self.assertEqual("Not updating Summaries...", self._call_wrapper('n'))

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ergxz8rk2#

我觉得上面的答案给出了一个太DRY的例子。我喜欢将设置阶段与运行代码分开。您不需要创建单独的 Package 器或使用side_effect。毕竟，input只是一个函数。
我的看法是这样的指挥

from django.core.management import BaseCommand

class Command(BaseCommand):

    def handle(self, *args, **options):
        accept = input("Would you like to run `update_summaries` now? [Yes/No]")
        if accept == 'y':
            self.stdout.write("Updating Summaries!")
            return
        self.stdout.write("Not updating Summaries...")

你可以写

from django.test.utils import captured_stdout
from unittest import mock

from django.core.management import call_command
from django.test import TestCase

class UpdateTestCase(TestCase):
    @mock.patch("my_app.management.commands.update.input", return_value="y")
    def test_yes(self, m):
        with captured_stdout() as stdout:
            call_command("update")
            output = stdout.getvalue()
        self.assertEqual("Updating Summaries!", output)

    @mock.patch("my_app.management.commands.update.input", return_value="n")
    def test_no(self, m):
        with captured_stdout() as stdout:
            call_command("update")
            output = stdout.getvalue()
        self.assertEqual("Not updating Summaries...", output)

赞(0）回复(0）举报 2023-04-22

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如何在Django测试中发送命令行输入响应

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