MySql order by count(*)

mjqavswn 于 2023-04-28 发布在 Mysql

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该任务是一个国家的名单，有超过10个客户我试图只显示的价值观，计数〉10在表中
我试过这个，但它没有过滤表：

select co.country, count(*) from sakila.country as co
inner join city as ci on co.country_id = ci.country_id
inner join address as ad on ci.city_id = ad.city_id
inner join customer as cu on cu.address_id = ad.address_id
group by co.country
order by count(*) > 10;

mysql

来源：https://stackoverflow.com/questions/76120944/mysql-order-by-count

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按热度按时间

2nbm6dog1#

通过只显示计数大于10的值，您需要使用having。having需要使用，当你想过滤聚合函数的结果时，e.g.计数、求和。

select co.country, count(*)
from sakila.country as co
inner join city as ci on co.country_id = ci.country_id
inner join address as ad on ci.city_id = ad.city_id
inner join customer as cu on cu.address_id = ad.address_id
group by co.country
having count(*) > 10;
order by count(*);

如果您仍然希望按计数排序结果，您仍然需要在en中设置order by

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MySql order by count(*)

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