numpy 如何使用Python中的AI和ML库编写Python程序来预测游戏的下一个结果(从两种颜色中选择一种颜色)

p3rjfoxz  于 2023-04-30  发布在  Python
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我想用Python使用LSTM技术制作一个程序,可以预测下一个结果,或者说从两个颜色中挑选一个颜色的概率,程序应该使用AI和ML库,来读取最后40个结果的模式,从而预测下一个结果。
那么我就做了如下的一个方案。

from keras.models import Sequential
from keras.layers import LSTM, Dense
import numpy as np

def predict_next_color_lstm(outcomes):
    if len(outcomes) < 40:
        return "Error: Number of outcomes provided is less than 40."

    # Convert string input to integer sequence
    seq = [0 if x == 'r' else 1 for x in outcomes]

    # Create rolling window of 40 outcomes
    X = []
    y = []
    for i in range(len(seq) - 40):
        X.append(seq[i:i + 40])
        y.append(seq[i + 40])
    X = np.array(X)
    y = np.array(y)

    # Reshape X to fit LSTM input shape
    X = np.reshape(X, (X.shape[0], X.shape[1], 1))

    # Create LSTM model
    model = Sequential()
    model.add(LSTM(50, input_shape=(40, 1)))
    model.add(Dense(1, activation='sigmoid'))

    # Compile the model
    model.compile(loss='binary_crossentropy', optimizer='adam')

    # Train the model
    model.fit(X, y, epochs=50, batch_size=32)

    # Predict the next outcome
    last_40 = seq[-40:]
    pred = model.predict(np.array([last_40]))
    return 'r' if pred < 0.5 else 'g'

def get_input():
    # ask user to enter ball color sequence of length 40
    ball_seq = input("Enter the ball color sequence of length 40 (e.g. rrggrrgrrgggrgrgrrggggrgrgrrgrgggrrgggg): ")
    return ball_seq

# _main_
ball_seq = get_input()
print("Prediction : ", predict_next_color_lstm(ball_seq))

但是我在执行它时经常得到以下错误:
C:\Users\Ashish\miniconda3\python.exe C:\Users\Ashish\Desktop\pyt_pract\test_prob1.py输入长度为40的球色序列(e.例如:rgggrrgrgrggrrgrrgrgrgrggggrrrrggrrggrgrg Traceback(最近一次通话):文件“C:\Users\Ashish\Desktop\pyt_pract\test_prob1.py”,第50行,打印(“预测:“,predict_next_color_lstm(ball_seq))文件“C:\Users\Ashish\Desktop\pyt_pract\test_prob1.在predict_next_color_lstm中的第23行,“py”,X = np。整形(X,(X.shape[0],X.shape[1],1))IndexError:元组索引超出范围

v64noz0r

v64noz0r1#

错误消息“IndexError:tuple index out of range”表示X数组的形状有问题。具体地说,X的维数似乎不是我们所期望的那样。
错误的一个可能原因是seq的长度小于40,这会导致一个空的X数组。要解决这个问题,您可以添加一个检查,以确保在创建40个结果的滚动窗口之前,seq的长度至少为40:

def predict_next_color_lstm(outcomes):
    if len(outcomes) < 40:
        return "Error: Number of outcomes provided is less than 40."

    # Convert string input to integer sequence
    seq = [0 if x == 'r' else 1 for x in outcomes]

    # Create rolling window of 40 outcomes
    X = []
    y = []
    if len(seq) >= 40:
        for i in range(len(seq) - 40):
            X.append(seq[i:i + 40])
            y.append(seq[i + 40])
        X = np.array(X)
        y = np.array(y)

        # Reshape X to fit LSTM input shape
        X = np.reshape(X, (X.shape[0], X.shape[1], 1))

        # Create LSTM model
        model = Sequential()
        model.add(LSTM(50, input_shape=(40, 1)))
        model.add(Dense(1, activation='sigmoid'))

        # Compile the model
        model.compile(loss='binary_crossentropy', optimizer='adam')

        # Train the model
        model.fit(X, y, epochs=50, batch_size=32)

        # Predict the next outcome
        last_40 = seq[-40:]
        pred = model.predict(np.array([last_40]))
        return 'r' if pred < 0.5 else 'g'
    else:
        return "Error: Number of outcomes provided is less than 40."

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