debugging 三重引号字符串注解使简单的python程序崩溃

sxpgvts3  于 2023-04-30  发布在  Python
关注(0)|答案(4)|浏览(86)

当我试图在代码中添加注解时,我发现了这个奇怪的问题。我使用了三引号字符串来注解,但程序崩溃,给出了以下错误:
IndentationError: unexpected indent
当我使用#注解三重引号字符串时,一切正常。有谁知道这个错误背后的原因以及如何修复它?
我的代码:

#This programs show that comments using # rather than """ """

def main():
    print("let's do something")
#Try using hashtag to comment this block to get code working
'''
    Note following block gives you a non-sense indent error
    The next step would be to consider how to get all the words from spam and ham
    folder from different directory. My suggestion would be do it twice and then
    concentrate two lists

    Frist think about the most efficient way
    For example, we might need to get rid off the duplicated words in the beginning

    The thoughts of writing the algorithem to create the dictionary

    Method-1:
    1. To append all the list from the email all-together
    2. Eliminate those duplicated words

    cons: the list might become super large

    I Choose method-2 to save the memory
    Method-2:
    1. kill the duplicated words in each string
    2. Only append elements that is not already in the dictionary

    Note:
    1. In this case, the length of feature actually was determined by the
    training cohorts, as we used the different English terms to decide feature

    cons: the process time might be super long
'''
    def wtf_python(var1, var2):
        var3 = var1 + var2 + (var1*var2)
        return var3

    wtfRst1 = wtf_python(1,2)
    wtfRst2 = wtf_python(3,4)

    rstAll = { "wtfRst1" : wtfRst1,
               "wtfRst2" : wtfRst2
    }
    return(rstAll)

if __name__ == "__main__":
    mainRst = main()
    print("wtfRst1 is :\n", mainRst['wtfRst1'])
    print("wtfRst2 is :\n", mainRst['wtfRst2'])
arknldoa

arknldoa1#

罪魁祸首

在函数定义中移动注解:

原因

由于三引号字符串是有效的pythonexp,因此应该将它们同样处理,即:在函数范围内。

因此

def main():
    print("let's do something")
    #Try using hashtag to comment this block to get code working
    '''
        Note following block gives you a non-sense indent error
        The next step would be to consider how to get all the words from spam and ham
        folder from different directory. My suggestion would be do it twice and then
        concentrate two lists

        Frist think about the most efficient way
        For example, we might need to get rid off the duplicated words in the beginning

        The thoughts of writing the algorithem to create the dictionary

        Method-1:
        1. To append all the list from the email all-together
        2. Eliminate those duplicated words

        cons: the list might become super large

        I Choose method-2 to save the memory
        Method-2:
        1. kill the duplicated words in each string
        2. Only append elements that is not already in the dictionary

        Note:
        1. In this case, the length of feature actually was determined by the
        training cohorts, as we used the different English terms to decide feature

        cons: the process time might be super long
    '''
    def wtf_python(var1, var2):
        var3 = var1 + var2 + (var1*var2)
        return var3

    wtfRst1 = wtf_python(1,2)
    wtfRst2 = wtf_python(3,4)

    rstAll = { "wtfRst1" : wtfRst1,
               "wtfRst2" : wtfRst2
    }
    return(rstAll)

if __name__ == "__main__":
    mainRst = main()
    print("wtfRst1 is :\n", mainRst['wtfRst1'])
    print("wtfRst2 is :\n", mainRst['wtfRst2'])

输出

let's do something
wtfRst1 is :
 5
wtfRst2 is :
 19
w46czmvw

w46czmvw2#

您应该将三引号字符串的缩进级别向右移动一个标记。
虽然三引号字符串经常用作注解,但它们是普通的Python表达式,因此它们应该遵循语言的语法。

vuv7lop3

vuv7lop33#

作为注解的三重引号字符串必须是有效的Python字符串。有效的Python字符串必须正确缩进。
Python会看到多行字符串,并对其求值,但由于没有给它分配变量,因此字符串在下一行中被丢弃。

mdfafbf1

mdfafbf14#

上述解决方案是不正确的。对于那些在Emacs 28中遇到过这个问题的人来说,像我一样花了几个小时为此感到沮丧的人,这个问题是一个已知的bug,并且在emacs 29中得到了修复。
请在此处遵循此指南:https://github.com/emacs-mirror/emacs/blob/master/INSTALL下载29:https://alpha.gnu.org/gnu/emacs/pretest/
将任何错误粘贴到ChatGPT并按照说明操作:)

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