简单方法

这第一种方法如果你，和javascript的定义“word”匹配。下面是一个更可定制的方法。
试试test.split(/\s*\b\s*/)它在单词边界（\b）上进行分割，并占用空白。

"hello how are you all doing, I hope that it's good! and fine. Looking forward to see you."
    .split(/\s*\b\s*/);
// Returns:
["hello",
"how",
"are",
"you",
"all",
"doing",
",",
"I",
"hope",
"that",
"it",
"'",
"s",
"good",
"!",
"and",
"fine",
".",
"Looking",
"forward",
"to",
"see",
"you",
"."]

工作原理。

var test = "This is. A test?"; // Test string.

// First consider splitting on word boundaries (\b).
test.split(/\b/); //=> ["This"," ","is",". ","A"," ","test","?"]
// This almost works but there is some unwanted whitespace.

// So we change the split regex to gobble the whitespace using \s*
test.split(/\s*\b\s*/) //=> ["This","is",".","A","test","?"]
// Now the whitespace is included in the separator
// and not included in the result.

更复杂的解决方案。

如果你希望像“isn`t”和“one-thousand”这样的词被当作一个词，而javascript regex把它们当作两个词，你需要创建自己的词定义。

test.match(/[\w-']+|[^\w\s]+/g) //=> ["This","is",".","A","test","?"]

工作原理

这匹配实际的话，标点符号字符分别使用交替.正则表达式[\w-']+的前半部分匹配您认为是单词的任何内容，后半部分[^\w\s]+匹配您认为是标点符号的任何内容。在这个例子中，我只是使用了任何不是单词或空格的东西。我也不过是一个+就结束了，这样多字符标点符号（如？！这是正确的书面！）被视为一个字符，如果你不想删除+。

使用这个：

[,.!?;:]|\b[a-z']+\b

请参见the demo中的匹配。
例如，在JavaScript中：

resultArray = yourString.match(/[,.!?;:]|\b[a-z']+\b/ig);

说明

• 字符类[,.!?;:]匹配括号内的一个字符
• 或（交替|）
• \b匹配字边界
• [a-z']+一个或多个字母或撇号
• \b字边界