这是我的代码副本：）这个游戏是我个人活动的一部分。所以在购买线索**（从：def game_hints）我想返回到def Game_process。**
import random
SCORE = 0
ROUNDS = 1
def player_stats():
print(f"SCORE: {SCORE} | ROUNDS: {ROUNDS}")
def game_hints():
print("Would you like purchase a hint for 5 points? [1/2]: ")
USER_HINT = int(input())
global SCORE
if USER_HINT == 1:
points -= 5
if Mystery_NUM % 2 == 0:
divisibility = "even"
else:
divisibility = "odd"
if player_guess > Mystery_NUM:
value = "smaller"
else:
value = "larger"
print(f"CLUE: Mystery Number is {divisibility} and try a {value} guess | -5 POINTS")
def Game_Process():
global ROUNDS
while True:
if ROUNDS <= 10:
Mystery_NUM = random.randrange(10)
print(Mystery_NUM) #remove before final product
print("Guess the num [1-10]: ")
USER_GUESS = int(input())
if USER_GUESS == Mystery_NUM:
print("\nGood Job! +5 Coins!")
global SCORE
SCORE = SCORE + 10
ROUNDS += 1
player_stats()
else:
print("Wrong! Try Again")
game_hints(USER_GUESS, Mystery_NUM)
else:
print("Game Over!")
Game()
def Game():
user_opt = input("\"Welcome to Guess Game\" \nPress [Y] to Play or [N] to Exit: ").lower()
if user_opt == "n":
print("Good bye!")
exit()
elif user_opt == "y":
Game_Process()
else:
print("Invalid Input! [1/2]")
Game()
Game()如下图所示，这是提示的功能。我能够调用这个函数，但唯一的问题是，在这个函数完成后，它改变了Myster_Num。
def game_hints():
print("Would you like purchase a hint for 5 points? [1/2]: ")
USER_HINT = int(input())
global SCORE
if USER_HINT == 1:
points -= 5
if Mystery_NUM % 2 == 0:
divisibility = "even"
else:
divisibility = "odd"
if player_guess > Mystery_NUM:
value = "smaller"
else:
value = "larger"
print(f"CLUE: Mystery Number is {divisibility} and try a {value} guess | -5 POINTS")
1条答案
按热度按时间aelbi1ox1#
首先，必须删除game_hints函数中的else语句，因为它会重新启动一个完整的GameProcess，因此确实会重新计算一个神秘的数字。
然后，当你退出game_hints并回到GameProcess时，你一定不能回到大循环，因为它确实会重新计算一个神秘的数字。解决方案是在每一轮中有一个内部循环，只有当玩家使用break关键字猜到正确的值时才退出。