我使用Preference-Tree来设置值。这是我的代码

fun getWorkingHours(): Map<String, String> {
    val branches = libraryBranchesLiveData.value!!
    val hoursByDay : MutableMap<String, String> = mutableMapOf()
    val daysOfWeek = listOf("Sun", "Mon", "Tue", "Wed", "Thu", "Fri", "Sat")

    if (branches[selectedBranchIdPositionInList].opened_time?.isEmpty() == true) {
        for (day in daysOfWeek) {
            hoursByDay[day] = "Closed"
        }
        return hoursByDay
    }

    for (day in daysOfWeek) {
        val hoursForDay = StringBuilder()
        var startHour : String? = ""

        for (workingHour in branches[selectedBranchIdPositionInList].opened_time!!) {
            Log.e("working hours: ", "workingHour:${workingHour}")
            val parts = workingHour!!.split(":", limit = 2)
            val dayRange = parts[0]
            val hours = parts[1]

            Log.e("working hours: ", "dayRange${dayRange}")
            Log.e("working hours: ", "hours${hours}")

            if (day in dayRange) {
                if (hoursForDay.isNotEmpty()) {
                    hoursForDay.append(", ")
                }
                hoursForDay.append(hours)
            }
        }

        if (hoursForDay.isNotEmpty()) {
            hoursByDay[day] = "$hoursForDay"
        } else {
            hoursByDay[day] = "Closed"
        }

        Log.e("working hours: ", "${hoursByDay}")
    }

    return hoursByDay
}

然后在这里调用它并设置值

findPreference<Preference>(getString(R.string.branch_info_monday_opening_time_preference_key))?.summary = branchDetailsViewModel.getWorkingHours()["Mon"]

但是它给予的这个函数是错误的这个函数的输出是
如果"opened_time": ["Sun - Thu:8:00 am-8:00 pm","Fri:8:00 am-12:00 pm"]，则：

Sun = 8:00 am-8:00 pm
Mon = Closed
Tue = Closed
Wed = Closed
Thu = 8:00 am-8:00 pm
Fri = 8:00 am-12:00 pm

我需要做一个函数，将日期和时间从一个数组中分离出来，这个数组是我从API中得到的，比如"opened_time": ["Sun - Thu:8:00 am-8:00 pm","Fri:8:00 am-12:00 pm"]。我想做一个函数来设置它在DayofWeek的行为，像这样：

Sun = 8:00 am-8:00 pm
Mon = 8:00 am-8:00 pm
Tue = 8:00 am-8:00 pm
Wed = 8:00 am-8:00 pm
Thu = 8:00 am-8:00 pm
Fri = 8:00 am-12:00 pm
// and Saturday it will be like this
Sat = Closed

// Get the day strings val (startDay, endDay) = dayRange.split(" - ") // Get their indices in the days list val (start, end, target) = listOf(startDay, endDay, day).map { daysOfWeek.indexOf(it) } // Check if the target day's index falls between the other two // Because the ranges are circular, the end day might have a lower index, // in which case we need to check from 'start' to the end of the list, // and from the beginning of the list to 'end' val inRange = if (start < end) target in start..end else target >= start || target <= end

1条答案

按热度按时间

hmmo2u0o1#

val parts = workingHour!!.split(":", limit = 2)
val dayRange = parts[0]

if (day in dayRange) {
    hoursForDay.append(hours)
}

你实际上并没有检查任何范围，你只是检查字符串day是否存在于字符串dayRange中。Monday 在 Sunday to Thursday 范围内，但"Mon"不在文本"Sun - Thu"中。您需要一些逻辑来将其实际解析为一个日期范围，然后检查目标日期是否福尔斯该范围内。
这有点棘手，因为范围是圆形的。一个快速的方法是这样的：

需要注意的一件事是，如果indexOf在列表中找不到匹配项，则会得到-1，这将始终使target <= end * 为true*。你可以用不同的方式来做（比如检查target in 0..start || target in end..daysOfWeek.lastIndex），但理想情况下，这永远不会发生，因为你应该早点验证这些字符串，只有当它们在列表中时才在这里检查它们。您可以添加一行代码，如assert(listOf(start, end, target).all { it > -1 })，以清楚地表明此函数期望处理它，并且它是需要处理的东西

赞(0）回复(0）举报 2023-05-05

android 如何制作一个功能来管理工作时间

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