关于不同agtype之间的可订购性：- https://age.apache.org/age-manual/master/intro/comparability.html
我在测试path和edge之间的有序性，我发现了这个奇怪的行为：-
将路径与具有p > e不等式的边进行比较：-

test=# SELECT *
FROM cypher('test', $$
        WITH [{id: 0, label: "label_name_1", properties: {i: 0}}::vertex,
            {id: 2, start_id: 0, end_id: 1, label: "edge_label", properties: {i: 0}}::edge,
           {id: 1, label: "label_name_2", properties: {}}::vertex
           ]::path as p
MATCH (n)-[e]-(m) RETURN p>e
$$) AS (e agtype);
  e   
------
 true
 true
 true
 true
(4 rows)

很公平，当我们将其与p < e不等式进行比较时，同样的结果也成立

test=# SELECT *
FROM cypher('test', $$
        WITH [{id: 0, label: "label_name_1", properties: {i: 0}}::vertex,
            {id: 2, start_id: 0, end_id: 1, label: "edge_label", properties: {i: 0}}::edge,
           {id: 1, label: "label_name_2", properties: {}}::vertex
           ]::path as p
MATCH (n)-[e]-(m) RETURN p<e
$$) AS (e agtype);
   e   
-------
 false
 false
 false
 false
(4 rows)

但是当我们把不等式改成e > p

test=# SELECT *
FROM cypher('test', $$
        WITH [{id: 0, label: "label_name_1", properties: {i: 0}}::vertex,
            {id: 2, start_id: 0, end_id: 1, label: "edge_label", properties: {i: 0}}::edge,
           {id: 1, label: "label_name_2", properties: {}}::vertex
           ]::path as p
MATCH (n)-[e]-(m) RETURN e>p
$$) AS (e agtype);
  e   
------
 true
 true
 true
 true
(4 rows)

我们又得到了一个与p > e不等式直接矛盾的结果
当我们检查e < p时，我们再次得到false

test=# SELECT *
FROM cypher('test', $$
        WITH [{id: 0, label: "label_name_1", properties: {i: 0}}::vertex,
            {id: 2, start_id: 0, end_id: 1, label: "edge_label", properties: {i: 0}}::edge,
           {id: 1, label: "label_name_2", properties: {}}::vertex
           ]::path as p
MATCH (n)-[e]-(m) RETURN e<p
$$) AS (e agtype);
   e   
-------
 false
 false
 false
 false
(4 rows)

再次，与前两个结果直接矛盾。
似乎在边和路径的情况下，不管哪个是哪个'〉'不等式产生真，而'〈'不等式产生假。
这是预期的行为还是错误？如果这是故意的行为那为什么？