你可以在开头和结尾字符之前使用否定的lookahed和lookbehing：

r'<(?!\s)([^>]*)?(?<!\s)>'

您可以匹配：

<[^<>\s](?:[^<>]*[^<>\s])?>

说明

• <按字面匹配
• [^<>\s]匹配除<>以外的单个字符或空白字符
• (?:非捕获组
• [^<>]*匹配0+除<或>以外的字符
• [^<>\s]匹配除<>以外的单个字符或空白字符
• )?关闭非捕获组并将其设为可选
• >按字面匹配

在替换中使用空字符串。
请参见regex demo。

import re
 
pattern = r"<[^<>\s](?:[^<>]*[^<>\s])?>"
txt = "<this should be removed> hello < world > </this should also be removed> this should stay"
result = re.sub(pattern, "", txt)
 
if result:
    print (result)

输出

hello < world >  this should stay

如果你想要空的<>，那么你可以使用in the replacement。

您可以将以下正则表达式的匹配项转换为空字符串。

(?<=<(?!\s))[^<>]*?(?=(?<!\s)>)

Demo
此表达式具有以下元素。

(?<=       Begin a negative lookbehind
  <        Match a literal
  (?!\s)   Use a negative lookahead to assert that the previous
           match is not followed by a whitespace character
)          End negative lookbehind
[^<>]*
?          Require previous match to match as few characters as possible
(?=        Begin a positive lookahead
  (?<!\s)  Use a negative lookbehind to assert that the following
           match is not preceded by a whitespace character
  >        Match a literal
)          End the positive lookahead

也许是这样的：/<\S[^>]*>/g：

const text = '<this should be removed> hello < world > </this should also be removed> this should stay';
const result = text.replace(/<\S[^>]*>/g, '');
console.log(result);