正如标题中所示，我想知道如何才能获得特定的div，而在同一层次结构中有许多其他div具有相同的：父、子和类名。

**网页抓取器：**BeautifulSoup

示例：

<div class="main>
 <div class="parent">
  <div class="css-1wi2w6s enb64yk4"/>
 </div>
 <div class="parent">
  <div class="css-1wi2w6s enb64yk4"/>
 </div>
 <div class="parent">
  <div class="css-1wi2w6s enb64yk4"/> //div i want to get
 </div>
 <div class="parent">
  <div class="css-1wi2w6s enb64yk4"/>
 </div>
</div>

我的目标是从顶部得到第三个子div。
我尝试的是：

rooms = doc.select_one('.css-1wi2w6s.enb64yk4 > div:nth-of-type(3)')

但它返回了一个错误。
替代解决方案：

def get_data(url):
    if url.startswith('link'):
        result = requests.get(url)
        doc = BeautifulSoup(result.text, 'html.parser')
        rooms = doc.find('div', {'class': 'css-1wi2w6s enb64yk4'}, string=True)
        z = rooms.find_next()
        x = z.find_next()
        c = x.find_next()
        v = c.find_next()
        b = v.find_next()
        n = b.find_next()
        m = n.find_next()
        l = m.find_next()
        k = l.find_next()
        j = k.find_next()
        h = j.find_next()
        for i in h:
            return i.string
    else:
        # rooms = doc.find_all('p', {'class':'css-b5m1rv er34gjf0'})
        # return rooms
        return "link"

在您的评论之后：

htmld_doc = """
<div class="main">
  <div class="parent">
    <div class="css-1wi2w6s enb64yk4">1</div>
  </div>
  <div class="parent">
    <div class="css-1wi2w6s enb64yk4">2</div>
  </div>
  <div class="parent">
    <div class="css-1wi2w6s enb64yk4">3</div>
  </div>
  <div class="parent">
    <div class="css-1wi2w6s enb64yk4">4</div>
  </div>
</div>
"""
doc = BeautifulSoup(htmld_doc, 'html.parser')
rooms = doc.find('div', {'class': 'parent:nth-of-type(3) .css-1wi2w6s.enb64yk4'}, string=True)
print(rooms)
for i in rooms:
    print(i.string)

类型错误：'NoneType'对象不可迭代