You need two additional APPLY operators with two different OPENJSON() calls. First call is with default schema and the result is a table with columns key , value and type . The second call is with explicit schema with the appropriate columns, defined using the WITH clause:

Table:

Table:

CREATE TABLE Data (
   CustomerID int,
   City nvarchar(50),
   Product nvarchar(max)
)
INSERT INTO Data
   (CustomerID, City, Product)
VALUES
   (1, N'Delhi', N'[{"Products": [{"Id": "1", "Name": "TV"}, {"Id": "2", "Name": "Laptop"}]}]'),
   (2, N'Bamgalore', N'[{"Products": [{"Id": "1", "Name": "TV"}, {"Id": "2", "Name": "Laptop"}, {"Id": "3", "Name": "Mobile"}]}]')

Statement:

SELECT d.CustomerID, j2.Id, j2.Name
FROM Data d
CROSS APPLY OPENJSON(d.Product, '$') j1
CROSS APPLY OPENJSON(j1.[value], '$.Products') WITH (
   Id nvarchar(10) '$.Id',
   Name nvarchar(50) '$.Name'
) j2

Result:

----------------------
CustomerID  Id  Name
----------------------
1           1   TV
1           2   Laptop
2           1   TV
2           2   Laptop
2           3   Mobile

You can apply the arrays, to get to the object values.

SELECT t.CustomerId, a.*
FROM YourCustomerProductsTable t
OUTER APPLY
(
   SELECT
     [ProductId] = CAST(JSON_VALUE(obj.value,'$.Id') AS INT)
   , [Product] = JSON_VALUE(obj.value,'$.Name')
   FROM OPENJSON(t.Product) AS arr
   CROSS APPLY OPENJSON(arr.value, '$.Products') AS obj
) a;