regex Python正则表达式：可能匹配括号内的多个字符

7vux5j2d 于 2023-05-19 发布在 Python

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我很想得到一些帮助，让正则表达式模式匹配字符串中的多个字符。
潜在输入

The paragraph E(1)
The paragraph E(1)(a)
The paragraph E(1)(a)(ii)
The paragraph E(1)(a)(ii) and paragraph G(1)(b)

产出

E(1)
E(1)(a)
E(1)(a)(ii)
E(1)(a)(ii)、G(1)(b)

到目前为止，我有下面的正则表达式

import re

# Wrong. Should be ["E(1)"]
re.findall("[A-Z]\(\d{1,3}\)\([a-z]\)","The paragraph E(1)")
>>> []

# Correct
re.findall("[A-Z]\(\d{1,3}\)\([a-z]\)","The paragraph E(1)(a)")
>>> ["E(1)(a)"]

# Wrong. Should be ["E(1)(a)(ii)"]
re.findall("[A-Z]\(\d{1,3}\)\([a-z]\)","The paragraph E(1)(a)(ii)")
>>> ["E(1)(a)"]

# Wrong. Should be ["E(1)(a)(ii)", "G(1)(b)"]
re.findall("[A-Z]\(\d{1,3}\)\([a-z]\)","The paragraph E(1)(a)(ii) and paragraph G(1)(b)")
>>> ["E(1)(a)", "G(1)(b)"]

regex

来源：https://stackoverflow.com/questions/76203309/python-regex-matching-potentially-multiple-characters-within-the-parentheses

1条答案

按热度按时间

mv1qrgav1#

anubhava提供了答案

re.findall("[A-Z]\(\d{1,3}\)(?:\([a-z]+\))*","The paragraph E(1)")
>>> ["E(1)"]

re.findall("[A-Z]\(\d{1,3}\)(?:\([a-z]+\))*","The paragraph E(1)(a)")
>>> ["E(1)(a)"]

re.findall("[A-Z]\(\d{1,3}\)(?:\([a-z]+\))*","The paragraph E(1)(a)(ii)")
>>> ["E(1)(a)(ii)"]

re.findall("[A-Z]\(\d{1,3}\)(?:\([a-z]+\))*","The paragraph E(1)(a)(ii) and paragraph G(1)(b)")
>>> ["E(1)(a)(ii)", "G(1)(b)"]

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regex Python正则表达式：可能匹配括号内的多个字符

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