我没有找到关于所有命名参数**kwargs如何在视图调用中的重写“get_context_data”方法中传递的信息。
有3种型号：

class User(models.Model):
    email = models.CharField(unique=True)
    company_id = models.IntegerField(blank=True, null=True)
    first_name = models.CharField(blank=True, null=True)
    last_name = models.CharField(blank=True, null=True)

class Company(models.Model):
    logo = models.CharField(blank=True, null=True)
    name = models.CharField(blank=True, null=True)
    full_name = models.CharField(blank=True, null=True)
    address = models.CharField(blank=True, null=True)
    phone = models.CharField(blank=True, null=True)
    email = models.CharField(blank=True, null=True)
    kpp = models.CharField(blank=True, null=True)
    okved = models.CharField(blank=True, null=True)
    bik = models.CharField(blank=True, null=True)

class Order(models.Model):
    user_id = models.IntegerField(blank=True, null=True)
    amount_total_cents = models.BigIntegerField()
    amount_mean_cents = models.BigIntegerField()
    created_at = models.DateTimeField()

模型之间的通信：
公司-用户1至M，用户-订单1至M
在视图中直接输出数据而不覆盖“get_context_data”方法没有问题。但是，在重写该方法并通过主键链接两个表时没有问题：

**1.**公司/urls.py

urlpatterns = [
    path('company/<int:pk>', CompanyShow.as_view(), name='company_show')
]

公司/views.py

class CompanyShow(DetailView):
    model = Company
    template_name = 'company/company_show.html'
    context_object_name = 'company'

    def get_context_data(self, **kwargs):
        context = super(CompanyShow, self).get_context_data(**kwargs)
        context['users'] = User.objects.filter(company_id = self.kwargs['pk'])
        return context

company_show.html

<p>ID: {{ company.id }}</p>
    <p>Name: {{ company.name }}</p>
    <p>Members:
    {% for user in users %}
        <li>
        <a href="{% url 'user:user_show' user.id %}">{{ user }}</a>
        </li>
    {% endfor %}
    </p>

**2.**user/urls.py

urlpatterns = [
    path('user/<int:pk>', UserShow.as_view(), name='user_show')
]

用户/views.py

class UserShow(DetailView):
    model = User
    template_name = 'user/user_show.html'
    context_object_name = 'user'

user_show.html

<p>ID: {{ user.id}}</p>
    <p>Name: {{ user.first_name }}</p>
    <p>Surname: {{ user.last_name }}</p>
    {% if user.company_id %}
        <a href="{% url 'company:company_show' user.company_id %}">
            Company profile (id {{ user.company_id }})
        </a>
    {% else %}
        No company
    {% endif %}

问题如下：

应该从**kwargs向order/ www.example.com传递什么匹配参数views.py以便根据“user_id”字段的“order”表中的“user”表“id”过滤所需对象的列表？根据结果，需要在.html中显示公司-下一步如何连接“用户”和“公司”表？

• 然而，困难在于当绑定按顺序进行时 *：

订购/urls.py

urlpatterns = [
    path('order/<int:pk>', OrderShow.as_view(), name='order_show')
]

订购/views.py

class OrderShow(DetailView):
    model = Order
    template_name = 'order/order_show.html'
    context_object_name = 'order'

    def get_context_data(self, **kwargs):
        context = super(OrderShow, self).get_context_data(**kwargs)
        context['users'] = User.objects.filter(id = self.kwargs['user_id'])  
        return context

order_show.html

<p> Member:
    {% for user in users %}
        <li>
        <a href="{% url 'user:user_show' user.id %}">{{ user }}</a>
        </li>
    {% endfor %}
    </p>

在所描述的实现中，错误：

Exception Type:     KeyError
Exception Value:    'user_id'