json 如何从XML字符串中删除xmlns部分？

s8vozzvw 于 2023-05-19 发布在其他

关注(0)|答案(2)|浏览(186)

我想从xml字符串中删除xmlns部分并将其转换为json。

string test = "<Behavior xmlns:xsi=\"http://www.w3.org/2001/XMLSchema-instance\" xmlns=\"http://www.adlibsoftware.com\">\r\n  <JobFolders>\r\n    <Error>${machine:description=RM1029-DEV:id=4FC4AF7C-AF61-45F9-BE86-49812C619F06}</Error>\r\n    <Work>${machine:description=RM1029-DEV:id=4FC4AF7C-AF61-45F9-BE86-49812C619F06}</Work>\r\n    <Input>\r\n      <DeleteEmptySubfolders>true</DeleteEmptySubfolders>\r\n    </Input>\r\n  </JobFolders>\r\n  <JobFiles>\r\n    <ProcessingLocation>\r\n      <Server>\r\n        <TransferSegmentSize unit=\"Kilobytes\">4096</TransferSegmentSize>\r\n      </Server>\r\n    </ProcessingLocation>\r\n    <Input>\r\n      <Naming>Resh</Naming>\r\n    </Input>\r\n  </JobFiles>\r\n</Behavior>";

我尝试使用下面的代码，但仍然无法删除它。任何帮助将是伟大的！

XmlDocument doc = new XmlDocument();

doc.LoadXml(test);

foreach (var node in doc)
{
    var el = node as XmlElement;
    
    if (el != null)
    {
        if (el.HasAttribute("xmlns"))
        {
            var ns = el.GetAttribute("xmlns");

            if (ns != null && ns == el.NamespaceURI)
            {
                el.RemoveAttribute("xmlns");
            }
        }
    }
}

string jsonText = JsonConvert.SerializeXmlNode(doc);

我期望的输出是：

{"Behavior":"JobFolders":{"Error":"${machine:description=RM1029-DEV:id=4FC4AF7C-AF61-45F9-BE86-49812C619F06}","Work":"${machine:description=RM1029-DEV:id=4FC4AF7C-AF61-45F9-BE86-49812C619F06}","Input":{"DeleteEmptySubfolders":"true"}},"JobFiles":{"ProcessingLocation":{"Server":{"TransferSegmentSize":{"@unit":"Kilobytes","#text":"4096"}}},"Input":{"Naming":"Resh"}}}}

我从上面的代码收到的输出：

{"Behavior":{"@xmlns:xsi":"http://www.w3.org/2001/XMLSchema-instance","JobFolders":{"Error":"${machine:description=RM1029-DEV:id=4FC4AF7C-AF61-45F9-BE86-49812C619F06}","Work":"${machine:description=RM1029-DEV:id=4FC4AF7C-AF61-45F9-BE86-49812C619F06}","Input":{"DeleteEmptySubfolders":"true"}},"JobFiles":{"ProcessingLocation":{"Server":{"TransferSegmentSize":{"@unit":"Kilobytes","#text":"4096"}}},"Input":{"Naming":"Resh"}}}}

JSON

来源：https://stackoverflow.com/questions/70307425/how-to-remove-xmlns-part-from-a-xml-string

2条答案

按热度按时间

xoefb8l81#

问题解决了我在这里添加了编辑的解决方案。谢谢你的时间！

string test = "<Behavior xmlns:xsi=\"http://www.w3.org/2001/XMLSchema-instance\" xmlns=\"http://www.adlibsoftware.com\">\r\n  <JobFolders>\r\n    <Error>${machine:description=RM1029-DEV:id=4FC4AF7C-AF61-45F9-BE86-49812C619F06}</Error>\r\n    <Work>${machine:description=RM1029-DEV:id=4FC4AF7C-AF61-45F9-BE86-49812C619F06}</Work>\r\n    <Input>\r\n      <DeleteEmptySubfolders>true</DeleteEmptySubfolders>\r\n    </Input>\r\n  </JobFolders>\r\n  <JobFiles>\r\n    <ProcessingLocation>\r\n      <Server>\r\n        <TransferSegmentSize unit=\"Kilobytes\">4096</TransferSegmentSize>\r\n      </Server>\r\n    </ProcessingLocation>\r\n    <Input>\r\n      <Naming>Resh</Naming>\r\n    </Input>\r\n  </JobFiles>\r\n</Behavior>";

            XmlDocument doc = new XmlDocument();
            doc.LoadXml(test);

            foreach (var node in doc)
            {
                var el = node as XmlElement;
                if (el != null)
                {
                    if (el.HasAttribute("xmlns") || el.HasAttribute("xmlns:xsi"))
                    {
                        var ns = el.GetAttribute("xmlns");
                        var ns1 = el.GetAttribute("xmlns:xsi");
                        if (ns != null && ns == el.NamespaceURI && ns1 != null && ns1!= el.NamespaceURI)
                        {
                            el.RemoveAttribute("xmlns");
                            el.RemoveAttribute("xmlns:xsi");
                        }
                    }
                }
            }

            string jsonText = JsonConvert.SerializeXmlNode(doc);

赞(0）回复(0）举报 2023-05-19

fhity93d2#

问题中的代码仅删除每个节点的1个属性。
这段代码实际上是在删除属性：

string test = "<Behavior xmlns:xsi=\"http://www.w3.org/2001/XMLSchema-instance\" xmlns=\"http://www.adlibsoftware.com\">\r\n  <JobFolders>\r\n    <Error>${machine:description=RM1029-DEV:id=4FC4AF7C-AF61-45F9-BE86-49812C619F06}</Error>\r\n    <Work>${machine:description=RM1029-DEV:id=4FC4AF7C-AF61-45F9-BE86-49812C619F06}</Work>\r\n    <Input>\r\n      <DeleteEmptySubfolders>true</DeleteEmptySubfolders>\r\n    </Input>\r\n  </JobFolders>\r\n  <JobFiles>\r\n    <ProcessingLocation>\r\n      <Server>\r\n        <TransferSegmentSize unit=\"Kilobytes\">4096</TransferSegmentSize>\r\n      </Server>\r\n    </ProcessingLocation>\r\n    <Input>\r\n      <Naming>Resh</Naming>\r\n    </Input>\r\n  </JobFiles>\r\n</Behavior>";

            XmlDocument doc = new XmlDocument();
            doc.LoadXml(test);

            foreach (var node in doc)
            {
                var el = node as XmlElement;
                if (el != null)
                {
                    while (el.HasAttributes)
                    {
                        XmlAttribute item = el.Attributes[0];
                        if (el.HasAttribute(item.Name) && item.Name.Contains("xmlns"))
                        {
                            var ns = el.GetAttribute(item.Name);
                            if (ns != null )
                            {
                                el.RemoveAttribute(item.Name);
                                Console.WriteLine($"Remove attriute: {item.Name}"); 
                            }
                        }
                    }
                }
            }

            string jsonText = JsonConvert.SerializeXmlNode(doc);
            Console.WriteLine(jsonText);
            Console.ReadLine();

赞(0）回复(0）举报 2023-05-19

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json 如何从XML字符串中删除xmlns部分？

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