Java Web GoogleSignin - GoogleIdTokenVerifier验证令牌字符串返回null

6jygbczu  于 2023-05-21  发布在  Java
关注(0)|答案(6)|浏览(378)

我正在将Google注册/登录添加到我的Web应用程序中,遇到了问题。
这是我的代码:

private static final HttpTransport transport = new NetHttpTransport();
private static final JsonFactory jsonFactory = new JacksonFactory();
private static final String MY_APP_GOOGLE_CLIENT_ID = "wouldntyouliketoknow";

public UsernamePasswordAuthenticationToken verify(final String idTokenString){
    
    GoogleIdTokenVerifier verifier = new GoogleIdTokenVerifier.Builder(transport, jsonFactory)
                                            .setAudience(Collections.singletonList(MY_APP_GOOGLE_CLIENT_ID))
                                            .build();

    try {
        GoogleIdToken idToken = verifier.verify(idTokenString);// <-- verifier.verify returns null !!!
        if (idToken != null) {
            Payload payload = idToken.getPayload();
            String email = payload.getEmail();
            if(Boolean.valueOf(payload.getEmailVerified())){
                UserJPA jpa = userRepository.findByEmail(email);
                if(jpa==null){
                    throw new UsernameNotFoundException("Cannot find user with email = "+email);
                }
                if(!jpa.isRegisterredWithGoogle()){
                    throw new UsernameNotFoundException("This user did not use the 'Register with google' option.");
                }
                bokiAuthenticationProvider.checkUserActiveAndUnlocked(jpa);

                return new UsernamePasswordAuthenticationToken(jpa.getUsername(), jpa.getPasswordHesh(), 
                        bokiAuthenticationProvider.getAuthorities(jpa.getUserHasRoleSecurityList()));
            }
        }else{
            System.out.println("The *idToken* object is null !!!");
        }
    } catch (GeneralSecurityException | IOException e) {
        e.printStackTrace();
    }

    throw new MyCustomException("Google token is invalid or has expired");
}

为了创建我的CLIENT_ID,我按照下面链接中的说明操作:
https://developers.google.com/identity/sign-in/web/devconsole-project
问题是verifier.verify一直返回null
我检查过了:

  • 我的用户没有注册与谷歌和数据库字段正确填写
  • 每次我尝试google_sign_in时,我都会从google得到不同的字符串标记
  • 我的CLIENT_ID在Google控制台中有效且处于活动状态。

更令人困惑的是,就在一个月前,这一切还运作得很好。我请了病假,当我回来的时候,我的老板用这个问题欢迎我。
有人知道可能发生了什么吗?

d5vmydt9

d5vmydt91#

我终于想明白了。
由于没有人知道如何帮助我,我放弃了指定的Google库,从头开始进行自己的令牌验证。
我在这里使用了google-token-verifier-url-tool:
https://www.googleapis.com/oauth2/v3/tokeninfo?id_token=XYZ123
在页面底部这里:
https://developers.google.com/identity/protocols/OpenIDConnect
我想知道如何破解JSON。
我所做的是,我用代码联系他们的在线工具,获得JSON响应并手动验证它。这是我的代码:

private Map<String,String> getMapFromGoogleTokenString(final String idTokenString){
        BufferedReader in = null;
        try {
            // get information from token by contacting the google_token_verify_tool url :
            in = new BufferedReader(new InputStreamReader(
                                        ((HttpURLConnection) (new URL("https://www.googleapis.com/oauth2/v3/tokeninfo?id_token=" + idTokenString.trim()))
                                        .openConnection()).getInputStream(), Charset.forName("UTF-8")));
            
            // read information into a string buffer :
            StringBuffer b = new StringBuffer();
            String inputLine;
            while ((inputLine = in.readLine()) != null){
                b.append(inputLine + "\n");
            }
            
            // transforming json string into Map<String,String> :
            ObjectMapper objectMapper = new ObjectMapper();
            return objectMapper.readValue(b.toString(), objectMapper.getTypeFactory().constructMapType(Map.class, String.class, String.class));
            
        // exception handling :
        } catch (MalformedURLException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        } catch(Exception e){
            System.out.println("\n\n\tFailed to transform json to string\n");
            e.printStackTrace();
        } finally{
            if(in!=null){
                try {
                    in.close();
                } catch (IOException e) {
                    e.printStackTrace();
                }
            }
        }
        return null;
    }
    
    // chack the "email_verified" and "email" values in token payload 
    private boolean verifyEmail(final Map<String,String> tokenPayload){
        if(tokenPayload.get("email_verified")!=null && tokenPayload.get("email")!=null){
            try{
                return Boolean.valueOf(tokenPayload.get("email_verified")) && tokenPayload.get("email").contains("@gmail.");
            }catch(Exception e){
                System.out.println("\n\n\tCheck emailVerified failed - cannot parse "+tokenPayload.get("email_verified")+" to boolean\n");
            }
        }else{
            System.out.println("\n\n\tCheck emailVerified failed - required information missing in the token");
        }
        return false;
    }
    
    // check token expiration is after now :
    private boolean checkExpirationTime(final Map<String,String> tokenPayload){
        try{
            if(tokenPayload.get("exp")!=null){
                // the "exp" value is in seconds and Date().getTime is in mili seconds
                return Long.parseLong(tokenPayload.get("exp")+"000") > new java.util.Date().getTime();
            }else{
                System.out.println("\n\n\tCheck expiration failed - required information missing in the token\n");
            }
        }catch(Exception e){
            System.out.println("\n\n\tCheck expiration failed - cannot parse "+tokenPayload.get("exp")+" into long\n");
        }
        return false;
    }
    
    // check that at least one CLIENT_ID matches with token values
    private boolean checkAudience(final Map<String,String> tokenPayload){
        if(tokenPayload.get("aud")!=null && tokenPayload.get("azp")!=null){
            List<String> pom = Arrays.asList("MY_CLIENT_ID_1",
                                             "MY_CLIENT_ID_2",
                                             "MY_CLIENT_ID_3");
            
            if(pom.contains(tokenPayload.get("aud")) || pom.contains(tokenPayload.get("azp"))){
                return true;
            }else{
                System.out.println("\n\n\tCheck audience failed - audiences differ\n");
                return false;
            }
        }
        System.out.println("\n\n\tCheck audience failed - required information missing in the token\n");
        return false;
    }
    
    // verify google token payload :
    private boolean doTokenVerification(final Map<String,String> tokenPayload){
        if(tokenPayload!=null){
            return verifyEmail(tokenPayload) // check that email address is verifies 
                && checkExpirationTime(tokenPayload) // check that token is not expired
                && checkAudience(tokenPayload) // check audience
                ; 
        }
        return false;
    }

一旦我有了这个详细的验证,我就能确切地看到错误在哪里。前端向我发送了一个无效的CLIENT_ID值。[抱怨,抱怨]我问了他们一百次,他们告诉我这些值匹配。呸!
因此,错误不是在我用于令牌验证的原始代码中的某个地方,而是在我的办公室中的通信错误。
为了安全起见,我将恢复到原始代码,这次使用正确的CLIENT_ID。尽管如此,我必须对谷歌图书馆提出一个抱怨-它从来没有告诉我为什么令牌验证失败。我花了好几天的时间才终于弄明白。我知道他们这么做是出于安全考虑,但缺乏支持还是让人恼火。

xienkqul

xienkqul2#

有类似的问题。这是如此愚蠢,但我只是在我的服务器上有错误的时间。我认为验证总是失败,因为令牌的到期时间在我的服务器时间宇宙中结束。

shyt4zoc

shyt4zoc3#

对于那些仍然有这个问题的人:
1.尝试python示例(https://developers.google.com/identity/sign-in/web/backend-auth#python),以确保您使用正确的CLIENT_ID,如果没有,您将看到具有正确CLIENT_ID的异常消息
1.使用1.31.3版本的com.google.api-client1.31.4版本的com.google.oauth-client
1.将com.google.api.client.json.gson.GsonFactory用作JsonFactory

g6ll5ycj

g6ll5ycj4#

我通过从客户端发送idToken而不是authToken解决了我的问题

vm0i2vca

vm0i2vca5#

不知道是否有人还在看这个,但来自谷歌GitHub的代码实际上为我解决了这个问题。https://github.com/googlearchive/gplus-verifytoken-java/tree/master/src/com/google/plus/samples/verifytoken
他们提到,该项目已不再积极维护,但仍作为这项工作的存档。

bqf10yzr

bqf10yzr6#

我发现了两个原因为什么它会发生。

  1. Sping Boot 服务器和前端库之间存在CLIENT_ID不匹配。
    1.使用Google登录时生成的令牌ID已过期。通常在1小时后过期。
    刷新授权令牌的解决方案:
    成功登录后,我们在响应对象上获得一个reloadAuthResponse方法。此外,我们还获得了expires_in属性,它给出了令牌过期的毫秒数。下面是使用它的代码片段。
const handleSuccessfulGoogleResponse = (response) => {
 console.log(response)
 const loginDetails = {
   name: response.profileObj.name,
   email: response.profileObj.email,
   tokenId: response.tokenId
 }
 //Do what is needed with the data
 refreshTokenGenerator(response);
}

const refreshTokenGenerator = res => {
 let refreshTime = (res.tokenObj.expires_in || 3600 - 50 * 60) * 1000;
 const refreshToken = async () => {
    console.log('running at ',new Date(Date.now()).toLocaleTimeString());
    const refreshedResponse = await res.reloadAuthResponse();
    refreshTime = (refreshedResponse.expires_in || 3600 - 50 * 60) * 
   1000;

   const newTokenId = refreshedResponse.id_token;
   //store the newTokenId and use it for the network calls
    setTimeout(refreshToken, refreshTime);
 }
 setTimeout(refreshToken, refreshTime);
}

这里,handleSuccessfulGoogleResponse()在成功登录时执行。我们在其中调用refreshTokenGenerator(),它使用expires_in属性(如果它存在,否则默认为3600ms)。然后,我们使用setTimeout()执行函数,在当前令牌过期之前生成新令牌。

相关问题