$new   = array();

foreach ($info as $v)
{
    // Normalize the key names
    $key = ucfirst($v['name1']);

    if (isset($new[$key]))
    {
        $new[$key] += $v['count'];
    }
    else
    {
        $new[$key] = $v['count'];
    }
}

然后print_r($new);会给予你这个：

Array
(
    [Type1] => 44
    [Type2] => 21
)

我的看法是。

function getTypeArray($arr, $type) {
    return array_filter($arr, function($item) use($type) {
        return strtolower($item['name1']) == $type;
    });
}

function sumArray($arr) {
    return array_sum(array_map(function($item) {
        return $item['count'];
    }, $arr));
}

$type1_count = sumArray(getTypeArray($info, 'type1'));
$type2_count = sumArray(getTypeArray($info, 'type2'));
print 'Type1: '.$type1_count;
print 'Type2: '.$type2_count;

最明显的解决方案是迭代数组：

$counts = array();

foreach($info as $elem){
    $counts[$elem['name1']] += $elem['count'];
}

var_dump($counts);

输出：

Warning: Undefined array key "type1"

Warning: Undefined array key "Type2"

Warning: Undefined array key "Type1"

Warning: Undefined array key "type2"
array(4) {
  ["type1"]=>
  int(27)
  ["Type2"]=>
  int(11)
  ["Type1"]=>
  int(17)
  ["type2"]=>
  int(10)
}

如果你希望type1和Type1是相同的键（不区分大小写），你可以这样做：

foreach($info as $elem) {
    $counts[strtolower($elem['name1'])] += $elem['count'];
}

输出：

Warning: Undefined array key "type1"

Warning: Undefined array key "type2"
array(2) {
  ["type1"]=>
  int(44)
  ["type2"]=>
  int(21)
}