像这样的东西应该可以做到：

//Get start date and end date from database

$start_time = strtotime($start_date);
$end_time = strtotime($end_date);
$date_list = array($start_date);

$current_time = $start_time;

while($current_time < $end_time) {
    //Add one day
    $current_time += 86400;
    $date_list[] = date('Y-m-d',$current_time);
}
//Finally add end date to list, array contains all dates in order
$date_list[] = $end_date;

基本上，将日期转换为时间戳，并在每个循环中添加一天。

使用PHP的DateTime库：

<?php

$start_str = '2012-03-31';
$end_str = '2012-04-05';

$start = new DateTime($start_str);
$end = new DateTime($end_str . ' +1 day'); // note that the end date is excluded from a DatePeriod

foreach (new DatePeriod($start, new DateInterval('P1D'), $end) as $day) {
        echo $day->format('Y-m-d'), "\n";
}

Source

试试这个：

<?php

  // Set the start and current date
  $start = $date = '2012-03-31';

  // Set the end date
  $end = '2012-04-05';

  // Set the initial increment value
  $i = 0;

  // The array to store the dates
  $dates = array();

  // While the current date is not the end, and while the start is not later than the end, add the next day to the array    
  while ($date != $end && $start <= $end)
  {
    $dates[] = $date = date('Y-m-d', strtotime($start . ' + ' . $i++ . ' day'));
  }

  // Output the list of dates
  print_r($dates);

超快版本

日期转换是昂贵的。我对表演很失望，所以我试着调整了一下速度。它更像是一个优化的案例研究，但我将把它留在这里，因为它几乎比平常快3倍。它的工作原理是减少date( )被调用的次数。

function listDaysBetween($from,$till) {

    if($till<$from) return[];            //  handle the obvious empty case

    $tsFrom = strtotime("$from 11:00");  //  middle of first day
    $tsTill = strtotime("$till 11:00");  //  middle of last day
    $tsDiff = $tsTill - $tsFrom;         //  seconds diff
    $diff = round($tsDiff/86400);        //  days diff; output length
    $ts = $tsFrom;                       //  $ts will follow us along
    $day = $from;                        //  $day will scan the range
    $days = [$day];                      //  put the first one in there

    while($diff-->0) {                   //  a disguised for-loop
        $ts+=86400;                      //  keep timestamp following
        $d = (int)($day[8].$day[9]);     //  get the day part (fast)

        if($d>27) {                      //  at the end of each month,
            $day = date("Y-m-d",$ts);    //  it's better to ask date()
        }else{                           //  otherwise we do it faster
            $d+=101; $d="$d";            //  zero-padding to 2 digits
            $day[8] = $d[1];             //  direct character replace
            $day[9] = $d[2];             //  is faster than substr()
        }
        $days[] = $day;                  //  build output array
    }

    return $days;
}

我希望你会喜欢这些恶心的把戏。对这段代码的许多部分尝试了许多方法，这个版本到目前为止是一个明显的赢家，但我愿意接受建议。（除了在静态变量中缓存以供后续调用之外。这是作弊我完全可以做到这一点，但仍然）。
more about this如果你喜欢。

• 注意：此函数没有输入控件，您至少需要一些正则表达式，以避免在使用虚假数据调用时意外出现无限循环。为了简洁起见，我省略了这几行。