你可以用键和值构建一个标准化的对象，然后过滤对象。

const
    array1 = [{ name: 'detail1', title: 'detail1' }, { name: 'detail2 ', title: 'detail2 ' }, { name: 'detail3', title: 'detail3' }, { name: 'detail4', title: 'detail4' }, { name: 'detail5', title: 'detail6' }, { name: 'detail7', title: 'detail7' }, { name: 'detail8', title: 'detail8' }],
    array2 = [{ name: 'detail1', title: 'detail1' }, { name: 'detail2 ', title: 'detail2 ' }, { name: 'detail3', title: 'detail3' }, { name: 'detail4', title: 'detail4' }],
    sortEntriesByKey = ([a], [b]) => a.localeCompare(b),
    filter = array2.reduce((r, o) => {
        Object
            .entries(o)
            .sort(sortEntriesByKey)
            .reduce((o, [k, v]) => (o[k] ??= {})[v] ??= {}, r);
        return r;
    }, {});
    absent = array1.filter((o) => {
        let f = filter;
        return !Object
            .entries(o)
            .sort(sortEntriesByKey)
            .every(([k, v]) => f = f[k]?.[v]);
    });

console.log(absent);

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编辑：你想要的对象在A而不是在B。理想的做法是遍历A，找出元素是否存在于B中。如果是，则不包括它。
在javacript中，当你使用“==”或“===”或其他数组搜索方法时，对象引用会被比较。
{} == {}将返回false。您可以在您的开发控制台中进行检查。
在这种情况下，您必须检查特定的属性。

var absent = array1.filter(e=>{
  let findInd = array2.findIndex((a)=>{
    return (a.name == e.name && a.title == e.title);});
return (findInd == -1); });

在内部的findIndex中，我根据一个条件查找索引。在filter方法中，只有当索引为-1（未找到）时才返回true。

这对我很有效：

let cart = [{
    "id": "6304a51af5726921c0dadd64",
    "qty": 1
  },
  {
    "id": "8704a51af5726921c0dadd64",
    "qty": 1
  },
  {
    "id": "4704a51af5726921c0dadd64",
    "qty": 1
  }
]

let cartList = [{
    "id": "6304a51af5726921c0dadd64",
    "qty": 1
  },
  {
    "id": "9704a51af5726921c0dadd64",
    "qty": 1
  }
]

let test = cart.some((element) =>
  cartList.some((e) => element.id === e.id)
);
console.log(" if any single object matched:", test);

let test1 = cart.filter((element) =>
  cartList.some((e) => element.id === e.id)
);
console.log("display matching objects :", test1);

const array1 = [
  { name: 'detail1', title: 'detail1' },
  { name: 'detail2 ', title: 'detail2 ' },
  { name: 'detail3', title: 'detail3' },
  { name: 'detail4', title: 'detail4' },
  { name: 'detail5', title: 'detail5' },
  { name: 'detail6', title: 'detail6' },
  { name: 'detail7', title: 'detail7' }
]

const array2 = [
  { name: 'detail1', title: 'detail1' },
  { name: 'detail2 ', title: 'detail2 ' },
  { name: 'detail3', title: 'detail3' },
  { name: 'detail4', title: 'detail4' },
]
const thirdArray = array1.filter((elem) => {
       return !array2.some((ele) => {
       return elem.name === ele.name
         });
       });