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需要帮助将此C代码转换为x86汇编来执行矩阵乘法。无法使用数据节，必须为结果矩阵动态分配空间。
我根据这些规则写了这个C代码。然而，将其转换为C代码是一个挑战。有什么建议告诉我该怎么做吗？
C代码是：

//use this program to convert to assembly
#include <stdio.h>
#include <stdlib.h>

int** matMult(int **a, int num_rows_a, int num_cols_a, int** b, int num_rows_b, int num_cols_b){
    //function describes a matrix multiplication code 
    int **result;

    result = (int**)malloc(sizeof(int*)*num_rows_a);
    for (int i = 0; i < num_rows_a; i++) {
         result[i] = malloc(sizeof(int)*num_cols_b);
        for (int j = 0; j < num_cols_b; j++) {

        // Initialize the element to zero.
         result[i][j] = 0;
            for (int k = 0; k < num_cols_a; k++) {
            // Accumulate the result
             result[i][j] += a[i][k] * b[k][j];
     }
  }
}
    return 0;
}

汇编代码（到目前为止）：

.global matmult
 
.text
matmult:
    prologue: # describes code that prepares the stack before executing the function
        push %ebp # pushes base pointer onto the stack, sets up the stack frame
        movl %esp, %ebp # moves value of stack pointer (esp) into base pointer (ebp)
        subl $20, %esp # subtracts 20 bytes from the stack pointer which allocates space on the stack

        # .equ is used to assign values to symbols
        .equ a, 4
        .equ num_rows_a, 8
        .equ num_cols_a, 12
        .equ b, 16
        .equ num_rows_b, 20
        .equ num_cols_b, 24
        .equ i, -4
        .equ j, -8
        .equ k, -12l
        .equ C, -16
        .equ result, -20
 
        movl num_rows_a(%ebp), %eax
        movl $4, %ecx
 
 
 
    epilogue: # trims stack to fixed allocated size
        movl %ebp, %esp
        pop %ebp # pops value from top of stack into pointer
        ret # returns control from function to calling node
 
done: 
    nop