您可以使用index(of来检查currNr是否存在于数组中。（类必须符合Equatable协议）

var arrayNr = ["1", "32", "100"]
let currNr = "32"
// Check to remove the existing element
if let index = arrayNr.index(of: currNr) {
    arrayNr.remove(at: index)
}
arrayNr.append(currNr)

假设你有一个字符串数组，即类型[String]。现在，如果字符串存在，则要删除该字符串。所以你只需要用这一行代码来过滤数组

stringArray= stringArray.filter(){$0 != "theValueThatYouDontWant"}

例如，你有一个这样的数组，你想移除“1”

let array = ["1", "32"]

只需拨打

array = array.filter(){$0 != "1"}

长解

sampleArray遍历自身，如果在退出循环之前存在要查找的值，则删除该值。

var sampleArray = ["Hello", "World", "1", "Again", "5"]
let valueToCheck = "World"

for (index, value) in sampleArray.enumerated() {
    if value == valueToCheck && sampleArray.contains(valueToCheck) {
        sampleArray.remove(at: index)
        break
    }
}

print(sampleArray) // Returns ["Hello", "1", "Again", "5"]

短解

sampleArray返回一个数组，其中包含所有不等于您正在检查的值的值。

var sampleArray = ["Hello", "World", "1", "Again", "5"]
let valueToCheck = "World"

sampleArray = sampleArray.filter { $0 != valueToCheck }

print(sampleArray) // Returns ["Hello", "1", "Again", "5"]