所以，我想做的是在Python的递归函数中调用这个异步函数。但它不起作用，我不知道为什么它不应该。这是我在hpx中异步函数的绑定，并试图在python中的递归函数中使用

hpx::shared_future<int> myAsyncFunction(py::function f, py::args args)
{
    return hpx::async([f, args]() {
        py::gil_scoped_acquire acquire;
        py::object result = f(*args);
        return result.cast<int>();
    });
}

import test
import pdb

test.init_hpx()

def fibonacci(n):
    # pdb.set_trace()
    if(n<2):
        return n
    
    n1 = test.new_async(fibonacci,n - 1)
    n2 = test.new_async(fibonacci,n - 2)

    if n1.is_ready() and n2.is_ready():
        return n1.get() + n2.get()

print(fibonacci(10))

但它不工作，我得到这个错误

None
Fatal Python error: PyThreadState_Get: the function must be called with the GIL held, but the GIL is released (the current Python thread state is NULL)
Python runtime state: initialized

Thread 0x00007f508b7fe640 (most recent call first):
  <no Python frame>

Thread 0x00007f509353a000 (most recent call first):
  File "/home/matrix/pyhpx/python_hpx/build/fib.py", line 17 in <module>

我试着导入python.h并调用PyGILState_Ensure，但也不起作用

hpx::shared_future<int> myAsyncFunction(py::function f, py::args args) {
    return hpx::async([f, args]() {
        PyGILState_STATE gstate = PyGILState_Ensure(); // Acquire the GIL
        py::object result = f(*args);
        // Release the GIL
        PyGILState_Release(gstate);

        return result.cast<int>();
    });
}