因此，对于一个赋值，我应该检查来自用户的输入，并确定是否：
1.如果输入中有字符：我打印一条错误消息，说这是一个无效的输入，并要求再次输入，直到它是有效的
1.如果输入中的数字少于6位：我打印一条错误消息，指出还剩x位数，并再次请求输入，直到它有效为止

int main() {
    int solutionArray[6];
    int guessArray[6];
    int indexArray[6];

    /*Creating the random numbers and asking for seed*/
    
    int seed;
    printf("Enter the integer value of the seed for the game: ");
    scanf("%d", &seed);
    srand(seed);

    /*Adding the randomized integers into solutionArray*/
    for(int i = 0; i < 6; i++){
            solutionArray[i] = rand() % 10;
            printf("%3d", solutionArray[i]);
        }
        printf("\n");

    /*Game interface*/
    printf("For each turn enter 6 digits 0 <= digit <= 9 \n");
    printf("Spaces or tabs in your response will be ignored. \n");

    /*Validating conditions of the user input*/
    char input[50];
    int error = 0;
    int enoughDigits = 0;

    do {
        printf("Enter your guess, 6 digits: ");
        scanf("%s", input);
        int numCount = 0;
        int remainder = 0;
        int maxLength = 6;

        // Checking to see if there are any characters other than digits and prints error
        for (int i = 0; i < 6; i++) {
            if (!isdigit(input[i])) {
                printf("ERROR: A character in your guess was not a digit or a white space\n");
                printf("\n");
                error = 1;
                break;
            }
        }

        /*Checking to see if enough digits have been inputted*/ 
        remainder = 6 - numCount;
        for (int i = 0; i < 6; i++){
            if (isdigit(input[i] == 1)){
                numCount++;
                if (numCount < maxLength && numCount != 0){
                enoughDigits = 1;
            }
                else{
                    printf("You need to enter %d digits to complete your guess \n", remainder);
            }
            error = 1;
            }
        }
        
        // Print the guess if there are no errors
        if (error == 0) {
            printf("Your guess was:\n");
            for (int i = 0; i < 6; i++) {
                guessArray[i] = input[i] - '0';
                printf("%2d", guessArray[i]);
            }
            printf("\n");
        }

        // Printing results of the guesses 
        int partialMatches = 0;
        int perfectMatches = 0;

       for (int i = 0; i < 6; i++) {
            partialMatches = 0;
            for (int j = 0; j < 6; j++) {
                if (solutionArray[i] == guessArray[j]) {
                    partialMatches++;
                    break;  // Exit inner loop after finding a partial match
                }
            }
            if (solutionArray[i] == guessArray[i]) {
                perfectMatches++;
                partialMatches--;
            }
        }
        if (perfectMatches == 6){
            printf("YOU DID IT! ! \n");
            error = 0;
            break;
        }
        printf("%d matches, %d partial matches\n",perfectMatches, partialMatches);
        error = 1; 

    } while (error == 1 || enoughDigits == 1);

return 0;
}

我的问题是，当用户输入例如“123”时，它应该打印出我需要再输入3个数字，但它只打印出“您猜测的字符不是数字或空格”。出于某种原因，它会打印该错误，而不管输入是什么。
下面是我的代码。先谢谢你了！