jquery 如何实现bxslider缩略图分页器Next prev按钮

pdsfdshx  于 2023-06-22  发布在  jQuery
关注(0)|答案(1)|浏览(149)

我正在使用bxslider,我试图缩略图寻呼机下一个上一个按钮来移动缩略图,但我无法实现,你能帮我整理这一个,所以我可以实现缩略图滑块与缩略图下一个上一个按钮。

<ul class="bxslider">
  <li><img src="images/1.jpg" alt="1" width="960" height="600" /></li>
  <li><img src="images/1aNicollet.jpg" alt="1" width="960" height="600" /></li>
  <li><img src="images/7.jpg" alt="1" width="960" height="600" /></li>
  <li><img src="images/100_2129.JPG" alt="1" /></li>
  <li><img src="images/408619_10151175168202229_1189668486_n.jpg" alt="1" width="960" height="600" /></li>
  <li><img src="images/134593849-jpg_215416.jpg" alt="1" width="960" height="600" /></li>
  <li><img src="images/beauty-dress-girl-photo-wallpaper-1920x1200.jpg" alt="1" width="960" height="600" /></li>
  <li><img src="images/meh.ro8908.jpg" alt="1" width="960" height="600" /></li>
  <li><img src="images/lilian-garcia-2011-05-02.jpg" alt="1" width="960" height="600" /></li>
</ul>

<div id="bx-pager">
     <a href="#" id="slider-prev">Previous</a>
     <a data-slide-index="0" href=""><img src="images/thumb/1.jpg" alt="1" /></a>
     <a data-slide-index="1" href=""><img src="images/thumb/1aNicollet.jpg" alt="1" /></a>
     <a data-slide-index="2" href=""><img src="images/thumb/7.jpg" alt="1" /></a>
     <a data-slide-index="3" href=""><img src="images/thumb/100_2129.JPG" alt="1" /></a>
     <a data-slide-index="4" href=""><img src="images/thumb/408619_10151175168202229_1189668486_n.jpg" alt="1" /></a>
     <a data-slide-index="5" href=""><img src="images/thumb/134593849-jpg_215416.jpg" alt="1" /></a>
     <a data-slide-index="5" href=""><img src="images/thumb/beauty-dress-girl-photo-wallpaper-1920x1200.jpg" alt="1" /></a>
     <a href="#" id="slider-next">Next</a>
</div>
t9eec4r0

t9eec4r01#

假设您正在寻找滑块下方的第二个上一个/下一个操作。
按如下方式调用滑块:

var slider = $('.bxslider').bxSlider({
pagerCustom: '#bx-pager'
});

$('a.pager-prev').click(function () {
var current = slider.getCurrentSlide();
slider.goToPrevSlide(current) -1;
});
$('a.pager-next').click(function () {
var current = slider.getCurrentSlide();
slider.goToNextSlide(current) +1;
});

jsFiddle:http://jsfiddle.net/defonic/2cc7F/

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