这里有一些完整的代码，我希望它对某人有用。注意，在这个示例中，关系不是相互的，这意味着如果John与玛丽有关系，则Mary不会自动也与John有关系（这更像是John跟随Mary的情况）。但它仍然是如何使用显式连接表进行自关联的示例。

let Sequelize = require('sequelize');
let sequelize = new Sequelize('test', 'test', 'test', {dialect: 'mysql'});

let Person = sequelize.define('Person', {
    name: Sequelize.STRING,
    gender: Sequelize.STRING,
    age: Sequelize.INTEGER
});

let PersonRelationship = sequelize.define('PersonRelationship' /* , more fields could be defined here */);

Person.belongsToMany(Person, {as: 'Relationships', through: PersonRelationship, foreignKey: 'from'});
Person.belongsToMany(Person, {as: 'ReverseRelationships', through: PersonRelationship, foreignKey: 'to'});

let john, mary;

sequelize.sync()
    .then(() => Person.create({name: 'John', gender: 'm', age: 25}))
    .then(p => john = p)
    .then(() => Person.create({name: 'Mary', gender: 'f', age: 21}))
    .then(p => mary = p)
    .then(() => john.addRelationship(mary))
    .then(() => john.getRelationships({where: {age: 21}}))
    .then(relationships => {
        for (let relationship of relationships) {
            console.log('Found relationship:', relationship.name);
        }
    });

关于第一个问题：选择21岁的人的所有关系。您的查询是正确的。

return People.findOne({
  where: { name: 'John' },
  include: [{
    required: false,
    model: People,
    as: 'relationships',
    where: { age: 21 }
  }]
});

对于第二个查询：选择所有有21岁或/和男性亲属的人。

People.findAll({
  include: [{
    required: true,
    model: People,
    as: 'relationships',
    where: {
      $or: [
        { age: 21 },
        { gender: 'Male' }
      ]
    }
  }]
});

希望这将有助于任何人谁遇到的职位