无法创建与Spring数据Neo4j的关系

92dk7w1h  于 2023-06-22  发布在  Spring
关注(0)|答案(1)|浏览(126)

我正在尝试为Neo4j创建一组CRUD REST API。一切都很好,除了我无法建立新的关系。这些实体是:

@Node("Movie")
@Getter @Setter  @AllArgsConstructor @ToString
public class Movie {

    @Id
    @GeneratedValue
    //@JsonProperty(access = JsonProperty.Access.READ_ONLY)
    private Long id;

    @Property("title")
    private String title;

    @Property("description")
    private String description;

    @Relationship(type = "ACTED_IN", direction = Relationship.Direction.INCOMING)
    private List<Roles actorsAndRoles;

    @Relationship(type = "DIRECTED", direction = Relationship.Direction.INCOMING)
    private List<Person directors;
}

 @Node("Person")
 @Getter @Setter @AllArgsConstructor @ToString
 public class Person {
 
     @Id @GeneratedValue
     private Long id;
 
     @Property("name")
     private String name;
 
     @Property("born")
     private String born;
 
 }

 @Getter @Setter @AllArgsConstructor @ToString
 @RelationshipProperties
 public class Roles{
 
     @RelationshipId
     private Long id;
 
     @TargetNode
     private Person person;
 
     @Property("roles")
     private List<String roles;
 }

这是我调用的控制器(类称为MovieController)方法:

@PostMapping
    public ResponseEntity create(@RequestBody Movie movie){
        try {
            movie.setId(null);
            return ResponseEntity.ok(movieService.save(movie));
        }
        catch(Exception e){
            return ResponseEntity.internalServerError().body(e.getMessage());
        }
    }

我在这里上传了代码:https://github.com/RosarioB/spring-boot-crud-rest-api-neo4j/tree/basic_crud
这是一个POST请求主体的示例,位于:http://localhost:8080/api/movies

{
    
   "title":"Matrix",
   "description":"Science fiction",
   "actorsAndRoles":[
       {
           "person":{
               "name":"Keanu Reeves",
               "born":"27-01-1963"
           }
       }
   ]
   

}

这就是答案:

{
    "id": 16,
    "title": "Matrix",
    "description": "Science fiction",
    "actorsAndRoles": [
        {
            "id": null,
            "person": {
                "id": 17,
                "name": "Keanu Reeves",
                "born": "27-01-1963"
            },
            "roles": null
        }
    ],
    "directors": null
}

不幸的是,在数据库中只创建了2个节点(一个Person和一个Movie),而没有创建关系。我希望也能创建ACTED_IN关系。
我做错了什么?非常感谢!

rhfm7lfc

rhfm7lfc1#

这是Sping Boot 3.1.0和Spring Data Neo4j的已知问题。您可以将以下代码段添加到configuration/SpringBootApplication类。有关该问题的信息是here。一旦发布了更新版本,就应该修复它。

@Bean
public Configuration cypherDslConfiguration() {
    return Configuration.newConfig()
        .withDialect(Dialect.NEO4J_5)
        .build();
}

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