的确，我是sqlite的新手，也许我只是在问一个非常琐碎的问题。
我想直接从我的python分析工具中将一些分析结果存储在sqlite表中。结果包含在一个自定义对象（一个类）中，我认为sqlite python文档中的“如何适应自定义Python类型到SQLite值”部分将是我问题的起点。
从这个例子中，我得到了这段代码，它不工作：

import sqlite3

class Point:
   def __init__(self, x, y):
      self.x = x
      self.y = y

   # define a __conform__ method to adapt the type
   def __conform__(self, protocol):
      if protocol == sqlite3.PrepareProtocol:
         return self.x, self.y

connection = sqlite3.connect('mydb.db')
cursor = connection.cursor()
cursor.execute("""
   CREATE TABLE IF NOT EXISTS Points (x REAL, y REAL)
   """)
connection.commit()

# the insert query takes two qmark style placeholder and the __conform__ method of Point is 
# actually returning a tuple with two values. 

# attempt passing a tuple with 1 point to the execute method.
cursor.execute("""
   INSERT INTO Points VALUES (?, ?)
   """, (Point(24.2, 22.1),))
# fails with a ProgrammingError: Incorrect number of bindings supplied. The current statement uses 2, and there are 1 supplied. 

# attempt to pass a tuple with 1 point to the execute many method.
cursor.executemany("""
   INSERT INTO Points VALUES (?, ?)
   """, (Point(24.2, 22.1),))
# fails with a ProgrammingError: parameters are of unsupported type

# attempt of passing a Point directly
cursor.execute("""
   INSERT INTO Points VALUES (?, ?)
   """, Point(24.2, 22.1))
# fails with a ProgrammingError: parameters are of unsupported type

# attempt to manually adapt the object
cursor.execute("""
   INSERT INTO Points VALUES (?, ?)
   """, Point(24.2, 22.1).__conform__(sqlite3.PrepareProtocol))
# works, but I can't believe that this is the expected behavior!

我的代码和文档中提供的代码（可以工作）的唯一区别是，我的对象提供了两个值，而不是1。
我还尝试了第二种方法，使用要注册的适配器函数，但结果相同。此外，我还尝试用namedplaceholder替换qmark占位符，并在适配器中从元组交换到字典，但没有成功。
我做错了什么？
谢谢你帮我解决这个问题！