我正在使用sqlite deleteSqlite制作一个todo应用程序，在删除过程中按下按钮时它不会删除，但我想知道为什么它会在热重绘时删除？

Future<void> _deleteTodoItem(int id, String text, bool isDone) async {
    await TodoModelDao().deleteTodo(id, text, isDone);
    refleshList();
  }
  Future<List<TodoModel>> _showAllData() async {
    var todoList = await TodoModelDao().getAllData();
    return todoList;
  }

  refleshList() {
    setState(() {
      _showAllData();
    });
  }

Future<void> deleteTodo(int id, String text, bool isDone) async {
    var db = await DatabaseHelper.dbAccess();

    await db.delete(TABLENAME, where: "$ID = ?", whereArgs: [id]);
  }
  Future<List<TodoModel>> getAllData() async {
    var db = await DatabaseHelper.dbAccess();

    List<Map<String, dynamic>> maps = await db.rawQuery("SELECT * FROM $TABLENAME");

    return List.generate(maps.length, (i) {
      var row = maps[i];
      return TodoModel(id: row[ID], text: row[TEXT]);

    });
  }

child: IconButton(
            onPressed: () {
              _deleteTodoItem(widget.todoModel.id, widget.todoModel.text,
                  widget.todoModel.isDone);
            },
            icon: const Icon(Icons.delete),
            color: Coloors.whiteColor,
            iconSize: 18,
          ),