我添加了一个名为true_if_reference_is_false的自定义验证规则，并向其传递了一个参数independent_financial_advisor。
因此，验证看起来像这样：

$this->validate($request, [
    'independent_financial_advisor' => 'required|boolean',
    'understand_objective' => 'required|boolean|true_if_reference_is_false:independent_financial_advisor',
    'confirm_objective' => 'required|boolean|true_if_reference_is_false:independent_financial_advisor',
    'understand_term_held' => 'required|boolean|true_if_reference_is_false:independent_financial_advisor',
    'tax_relief' => 'required|boolean|true_if_reference_is_false:independent_financial_advisor'
]);

您需要在App\Providers\AppServiceProvider.php Import Facade Validator中定义此验证规则。

use Illuminate\Support\Facades\Validator;

然后在boot方法中定义规则：

Validator::extend('true_if_reference_is_false', function ($key, $value, $parameters, $validator) {
    $request = request();
    $keyReference = $parameters[0];
    if ($request->has($parameters[0]) && $request->$keyReference == false)
        return (bool)$request->$key;
    else
        return true;
});

希望这有帮助：）

'independent_financial_advisor' => 'required|boolean',
'understand_objective' => 'boolean|required_if:independent_financial_advisor,0,false',
'confirm_objective' => 'boolean|required_if:independent_financial_advisor,0,false',
'understand_term_held' => 'boolean|required_if:independent_financial_advisor,0,false',
'tax_relief' => 'boolean|required_if:independent_financial_advisor,0,false',

有关更多验证规则，请查看laravel文档www.example.com https://laravel.com/docs/5.7/validation#rule-required-if

$validator = Validator::make($request->all(), [
                'tax_relief'=>['required','in:true']
            ]);
if ($validator->fails()) {
                return response()->json($validator->errors());
}

使用Laravel 8，我通过以下方式解决了这个问题：

// MyFormRequest.php
public function rules()
{
    return [
        'bool_attrib_1' => [
            'required',
            'bool',
            function ($attribute, $value, $fail) {
                if (! $value && ! request('bool_attrib_2')) {
                    $fail('You must select either Bool Attrib 1 or Bool Attrib 2.');
                }
            },
        ],
        'bool_attrib_2' => [
            'required',
            'bool',
            function ($attribute, $value, $fail) {
                if (! $value && ! request('bool_attrib_1')) {
                    $fail('You must select either Bool Attrib 1 or Bool Attrib 2.');
                }
            },
        ],
    ];
}

我今天遇到了这个问题，并使用条件验证闭包解决了它（因为它在整个应用程序中只使用一次）。
基本上，用户必须根据需要标记phone或email字段。它们可以都是true，也可以只有一个是true，但不能都是false。
技巧是use闭包中的request对象，以访问需要作为验证检查一部分的其他字段。字段是array强制转换属性的一部分，这就是为什么它具有.的原因。

'required_order_fields.phone' => [
                Rule::in(["true", "false"]),
                function ($attribute, $value, $fail) use ($request) {
                    if ($value === "false" && $request->input('required_order_fields.email') === "false") {
                        $fail('The '.$attribute.' must be required if the email customer field is not required');
                    }
                },
            ],
            'required_order_fields.email' => [
                Rule::in(["true", "false"]),
                function ($attribute, $value, $fail) use ($request) {
                    if ($value === "false" && $request->input('required_order_fields.phone') === "false") {
                        $fail('The '.$attribute.' must be required if the phone customer field is not required');
                    }
                },
            ],

Validator::extend('true_if_reference_is_false', function ($key, $value, $parameters, $validator) {
        $request = request();
        $keyReference = $parameters[0];
        if ($request->has($parameters[0]) && $request->$keyReference == false)
            return (bool)$request->$key;
        else
            return true;
    });

    Validator::extend('false_if_reference_is_true', function ($key, $value, $parameters, $validator) {
        $request = request();
        $keyReference = $parameters[0];
        if ($request->has($parameters[0]) && $request->$keyReference == true)
            return !(bool)$request->$key;
        else
            return true;
    });